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vba Query to get the last record of each day in table.

Hello all

I have a table that I need to have a query to get the last record for each day.

For sake of this example, I will keep it simple.

Let us call the table [dta]

Let us assume the fields are.
[ID]
[Info1]
[Info2]
[Info3]
[Date]

Now then I know how to use Dmax("ID","dta","Date") To get the last record.  However I need that Last record for each and every day...????????
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wlwebb
Asked:
wlwebb
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2 Solutions
 
jerryb30Commented:
Select max(ID), [Date] from dta group by [date]
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jerryb30Commented:
Select ID, info1, info2, info3, [date] from dta where id in(Select max(ID) from dta group by [date])
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GrahamMandenoCommented:
I'm not clear whether you want:

a) The record with the highest [ID] value for each date (where the [Date] field contains only a date with no time part), OR

b) The record with the highest date/time value in the [Date] field for each date ONLY in the [Date] field (where the [Date] field contains BOTH a date part AND a time part)

I assume that [ID] contains a unique value.

This query should satisfy case (a) above:

SELECT * FROM dta 
    WHERE [ID]=(SELECT TOP 1 [ID] FROM dta as X 
         WHERE X.[Date]=dta.[Date] 
         ORDER BY [ID] desc);

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This query should satisfy case (b):

SELECT * FROM dta 
    WHERE [ID]=(SELECT TOP 1 [ID] FROM dta as X 
         WHERE DateValue(X.[Date])=DateValue(dta.[Date]) 
         ORDER BY [Date] desc);

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wlwebbAuthor Commented:
Thank you!
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wlwebbAuthor Commented:
GrahamMandeno THANK YOU for thinking past the original limited question!!!!!!! Much appreciated.
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