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"combine" the results of a stored proc?

Is it possible to take the results of a stored proc and then SUM one of the columns, leaving all the other columns as they are?

The two rows returned are identical except for the amount.

sumexecsp
0
Tom Knowlton
Asked:
Tom Knowlton
  • 2
2 Solutions
 
appariCommented:
if possible change it in the stored procedure itself, by using grouping. post your existing procedure script here.
0
 
ValentinoVBI ConsultantCommented:
You can put the results of the SP into a temporary table or table variable through the following syntax:

INSERT INTO #YourTempTable
EXEC ...

This assumes that #YourTempTable already exists.  Once the data is in the temp table, you can use a regular SELECT statement to manipulate it any way you'd like.
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Tom KnowltonWeb developerAuthor Commented:
Here is the current T-SQL:

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

IF EXISTS (SELECT * FROM dbo.sysobjects WHERE id = object_id(N'[dbo].[Marketing_Plan_RepairBidDetail_Get]') and OBJECTPROPERTY(id, N'IsProcedure') = 1)

DROP PROCEDURE [dbo].[Marketing_Plan_RepairBidDetail_Get]

GO

CREATE PROCEDURE [dbo].[Marketing_Plan_RepairBidDetail_Get]

@RepairBidID	int,
@RepairBidSID	int

AS


select 
rb.BidCompany
,rih.RprEstCompletionDays
,subselRU.sumofamt
,rb.BidDocID 
,rb.BidDocSID
,rb.AssetTaskID
,rb.AssetTaskSID
,rb.RepairBidID
,rb.RepairBidSID
,rb.StatusID
From RepairBidForm rbf
join RepairBid rb on rb.RepairBidFormID = rbf.RepairBidFormID 
and rb.RepairBidFormSID = rbf.RepairBidFormSID
join RprInspHeader rih on rb.RepairBidID = rih.RepairBidID
join (select ru2.RepairBidID, ru2.RepairBidSID, sum(Amt) as sumofamt
from RepairUnit ru2
group by 
ru2.RepairBidID, 
ru2.RepairBidSID, 
(Amt)) subselRU on rb.RepairBidID = subselRU.RepairBidID
join RepairItem ri on rbf.RepairBidFormID = ri.RepairBidFormID
where 
subselRU.RepairBidID = @RepairBidID and subselRU.RepairBidSID = @RepairBidSID
group by
rb.BidCompany
,rih.RprEstCompletionDays
,subselRU.sumofamt
,rb.BidDocID
,rb.BidDocSID
,rb.AssetTaskID
,rb.AssetTaskSID
,rb.RepairBidID
,rb.RepairBidSID
,rb.StatusID
GO




 

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Tom KnowltonWeb developerAuthor Commented:
Thank you.
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