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Java JVM Method Invocation

Posted on 2013-02-01
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Last Modified: 2013-02-01
Method Invocation
When the following Java code is run by the JVM, what is the order of method invocation? Assume the class Foo has not been loaded yet.
new Foo().getName();

a) <init>, <clinit>, getName
b) getName, <clinit>, <init>
c) <clinit>, <init>, getName
d) None of the above
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Question by:javaagile
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6 Comments
 
LVL 37

Expert Comment

by:zzynx
ID: 38843282
We're not allowed/here to do your homework. Sorry.
0
 

Author Comment

by:javaagile
ID: 38843351
this is not homework. I need to understand what happens in jvm internally when a method is invoked.
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LVL 37

Accepted Solution

by:
zzynx earned 500 total points
ID: 38843387
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LVL 37

Expert Comment

by:zzynx
ID: 38843423
Thanx 4 axxepting
0
 
LVL 14

Expert Comment

by:CPColin
ID: 38844398
Hi javaagile,

This is one of those cases where "try it and see" would have been the best advice anybody could give you. You could have done something like this and found the answer in much less time:

public class Foo
{
   static
   {
      System.out.println("In <clinit>");
   }

   public Foo()
   {
      System.out.println("In <init>");
   }

   public void getName()
   {
      System.out.println("In getName()");
   }
}

Open in new window


If you're really interested in learning and using Java, you'll do thousands of little investigations just like this. Best get used to it, if you ask me.
0
 

Author Comment

by:javaagile
ID: 38845449
Thanks CPColin, I knew this execution order but was not familiar with terms like <clinit> and <init>
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