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djfenom

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Alphabetise after explode

I have a blog page which lists tags relating to particular blog articles.

The tags are displayed on the page and are populated from a database.

Tags are allocated to a particular blog and are then held in one field separated by a comma.

The tags are written to the page using the following code:

$query_RStags = "SELECT DISTINCT blogTags FROM news";
$RStags = mysql_query($query_RStags, $conn) or die(mysql_error());
$row_RStags = mysql_fetch_assoc($RStags);
$totalRows_RStags = mysql_num_rows($RStags);

$alltags = array();
		do { 
			foreach(explode(',', $row_RStags['blogTags']) as $tag) {
				$taglink = strtolower(str_replace(' ','_',$tag));
				if (!in_array($tag, $alltags)) {
					if ($tag !="") {
						if ($_GET['cat'] == $taglink) { $state = ' class="onstate"'; } else { $state = ''; }
						array_push($alltags, $tag);
						$catcount = mysql_query("SELECT * FROM news WHERE blogTags LIKE '%" . $tag . "%'", $conn);
						$catrows = mysql_num_rows($catcount);
						echo "<li><a href=\"/news/category/{$taglink}\"{$state}>{$tag}</a> ({$catrows})</li>\n";
					}
				}
			}

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This works great, but my question is, how do I get the tags to come out in alphabetical order? I've looked at Sort, but can't work out where I would use it?

Thanks,

Chris
Avatar of Meir Rivkin
Meir Rivkin
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store the echo output in array, after iteration, sort and echo:


$query_RStags = "SELECT DISTINCT blogTags FROM news";
$RStags = mysql_query($query_RStags, $conn) or die(mysql_error());
$row_RStags = mysql_fetch_assoc($RStags);
$totalRows_RStags = mysql_num_rows($RStags);

$alltags = array();
$alltags_echos = array();
		do { 
			foreach(explode(',', $row_RStags['blogTags']) as $tag) {
				$taglink = strtolower(str_replace(' ','_',$tag));
				if (!in_array($tag, $alltags)) {
					if ($tag !="") {
						if ($_GET['cat'] == $taglink) { $state = ' class="onstate"'; } else { $state = ''; }
						array_push($alltags, $tag);
						$catcount = mysql_query("SELECT * FROM news WHERE blogTags LIKE '%" . $tag . "%'", $conn);
						$catrows = mysql_num_rows($catcount);
						$alltags_echos[$tag] = "<li><a href=\"/news/category/{$taglink}\"{$state}>{$tag}</a> ({$catrows})</li>\n";
					}
				}
			}

ksort($alltags_echos);

foreach ($alltags_echosas $key => $val) {
echo  $val;
}

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btw, u don't need array $alltags anymore, cause u have it in the $alltags_echos dictionary as the keys.
Avatar of djfenom
djfenom

ASKER

Thanks sedgwick, before I had:

c tag (1)
b tag (1)
a tag (1)

After adding your code it now comes out as:

c tag (1)
b tag (1)
c tag (1)
a tag (1)
b tag (1)
c tag (1)

Any ideas?

Chris
the $tag is unique ?
Avatar of djfenom

ASKER

Not necessarily, more than one article could use the same tag, that's why I used DISTINCT in my query.
but the result of your query are distinct (as you say), which means no multiple $tags should be queried, right?
Avatar of djfenom

ASKER

No, it should just show them once.
Suggest you try ordering the query results set like this:

$query_RStags = "SELECT DISTINCT blogTags FROM news ORDER BY blogTags";
Avatar of djfenom

ASKER

Sorry for the delay.

The order by won't work as the field blogTags can have multiple tags in it separated by a comma.
ASKER CERTIFIED SOLUTION
Avatar of Ray Paseur
Ray Paseur
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Avatar of djfenom

ASKER

Thanks Ray, unfortunately it's not an option to change the database design at this stage.

Where would I put var_dump() in my code?
I have no idea where to put var_dump()!  I cannot understand the code well enough because of the function overloading. You might try deconstructing this statement to get an intermediate array that you could visualize with var_dump()

foreach(explode(',', $row_RStags['blogTags']) as $tag) {
...unfortunately it's not an option to change the database design at this stage.
And it's not an option to get correct output from a misdesigned data base!

A professional would make a copy of the data base, modify the structure, revise the code, test the new data base, and once satisfied that things were working correctly, push the build to enable the new functionality.  It could reasonably be expected to take the better part of a day.  And you would probably need to take the site down for a few minutes during the switchover  We all make mistakes, and the design of this data base is a mistake.  It should be corrected

And a professional would not try to learn PHP by copying Dreamweaver code, either.  If you want to get a foothold in how to write PHP, this book will give you a head start.  By the time you get to page 325, you'll never need to look to Dreamweaver again!
http://www.amazon.com/PHP-MySQL-Web-Development-Edition/dp/0672329166/
Avatar of djfenom

ASKER

Don't have a cow man!

So I'm clearly not a 'professional' like you, you've ascertained that, I've given you the points, now move on and don't shoot me down.