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  • Status: Solved
  • Priority: Medium
  • Security: Public
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Removing empty lines in XSL

I have the following xsl code in using  <xsl:stylesheet version="1.1"
      xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
      xmlns:fo="http://www.w3.org/1999/XSL/Format">



<xsl:template name="ABC">ABC|<xsl:value-of select="."/>|      
</xsl:template>


value is read in a GUI screen and stored usign above ABC.
The value read is used to form a segment in a message that would have
ABC|text entered

Problem is when the user enters no text and a carriage return because this eventually causes a problem in a gateway.

example:
Entered text1. <carriage return>
Carriage return.
Entered text2. <carriage return>

The result is:

ABC|Entered text1. <carriage return>
ABC|Carriage return.
ABC|Entered text2. <carriage return>

I would want the result to be:

ABC|Entered text1. <carriage return>
ABC|Entered text2. <carriage return>
0
Johannne1
Asked:
Johannne1
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1 Solution
 
Geert BormansCommented:
make two templates

<xsl:template name="ABC[normalize-space(.)]">ABC|<xsl:value-of select="."/>|      
</xsl:template>
<xsl:template name="ABC[not(normalize-space(.))]"/>
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Johannne1Author Commented:
Thanks Gertone. for the post. I will try out within 2 hours.
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Johannne1Author Commented:
Hi Gertorne,
So far I could not get this to work. I will have to try again tomorrow evening.
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Geert BormansCommented:
Ah, I see, for one reason or another you have named templates where I expected matching templates

Try this instead

    <xsl:template name="ABC">
        <xsl:if test="normalize-space(.)">
            <xsl:text>ABC|</xsl:text>
            <xsl:value-of select="."/>
            <xsl:text>|</xsl:text>
        </xsl:if>
    </xsl:template>
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