Link to home
Start Free TrialLog in
Avatar of sirbounty
sirbountyFlag for United States of America

asked on

Inserting records; increment weekly

Looking for a function in SQL (2008) where I can repeatedly enter a new row, incrementing two date fields (by 7 days each time)...

Insert into MyTable Values (Field1, Field2, StartDate, EndDate)

With start date beginning at 02/04/2013, end date beginning at 2/10/2013 and both continuing until year-end (or so)...
Avatar of Ioannis Paraskevopoulos
Ioannis Paraskevopoulos
Flag of Greece image

You may use a cursor(for the repetition) and DATEADD function for the increment of the dates

Giannis
Avatar of sirbounty

ASKER

cursor?
Here is a sample code:

DECLARE @MyTable Table
(
	StartDate DATETIME,
	EndDate DATETIME
)

DECLARE @InitialStartDate DATETIME
DECLARE @InitialENDDate DATETIME

DECLARE @StopDate DATETIME

SET	@InitialStartDate = '20130402'
SET	@InitialENDDate = '20131002'
SET	@StopDate = '20131231'


DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME

Insert into @MyTable Values (@InitialStartDate,@InitialENDDate)


DECLARE IncrementalInsert CURSOR FOR
SELECT	MAX(StartDate), MAX(EndDate)
FROM	@MyTable 

OPEN IncrementalInsert 
FETCH NEXT FROM 
IncrementalInsert 
INTO @StartDate, @EndDate

WHILE @StartDate<@StopDate
BEGIN 

	SET @StartDate = DATEADD(dd,7,@StartDate)
	SET @EndDate = DATEADD(dd,7,@EndDate)

	--INSERT INTO @MyTable Values ( @StartDate, @EndDate)
	SELECT * FROM @MyTable


	FETCH NEXT FROM IncrementalInsert INTO @StartDate, @EndDate
END 
 
CLOSE IncrementalInsert 
DEALLOCATE IncrementalInsert

Open in new window


Giannis
In my scenario i create a table variable in order to store the dates. You don't need to do that as you already have the table, but my code is just a demonstration.

For simplicity i have only the date fields but you may have your other fields too.

Then i declare my starting dates and the date after which i need the loop to stop.

After that, i insert the first row and in the loop i insert the dates incremented by 7.

When my start date becomes greater than the 'StopDate' i quit the loop.

I hope it is clear what i am doing....

Giannis
Still going through it, but that helps some.
When I run it, it doesn't seem to be incrementing as is.

I get the date setup, and the loop, but I'm not sure about the table setup.
In your example, you declare a table with only start & end dates.  
Would I add the other columns in my table to that (and their data types)?
How would I reference that to my actual table name?

Does this section

SELECT      MAX(StartDate), MAX(EndDate)
FROM      @MyTable

Actually state to grab what's already in the rows?  I'm okay with that method, just trying to understand the code...

I'm having trouble with the while definition as well...
WHILE @StartDate<@StopDate
StartDate will always be < StopDate, won't it?
The table variable is just to show you an example. You should actualy use your table.

The select max is to just get your starting dates if you actually have data in your table.

If you see every time you enter in the loop it increments the @StartDate so at some point it will be greater than the @StopDate.

Giannis
ASKER CERTIFIED SOLUTION
Avatar of Scott Pletcher
Scott Pletcher
Flag of United States of America image

Link to home
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
That code gives me :Incorrect syntax near 'testdata'
on the line that reads:

INSERT INTO dbo.tblcollaboncall (NewID, startDate, endDate, 'testdata',1,0)
Ah, took me a bit to figure it out, but that ended up being quick and simple once I got my head wrapped around it - thanx! :^)
Sweet!

If you need to read data from an existing table -- that is, take row(s) from an existing table and combine them with all the dates -- you can do this:


INSERT INTO dbo.MyTable ( field1, field2, startDate, endDate )
SELECT tn.field1, tn.field2, DATEADD(DAY, num * 7, @startDate), DATEADD(DAY, num * 7 + 6, @startDate)
FROM dbo.table_name tn
CROSS JOIN cteTally
WHERE
    num BETWEEN 0 AND DATEDIFF(DAY, @startDate, @last_date_to_generate) / 7 - 1
    --AND tn.col_name = 'some_value' AND ...
ORDER BY
    3