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3D " pattern and " pattern

Posted on 2013-02-06
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Last Modified: 2013-02-06
can you have this pattern work for both
<div class=3D"gmail_quote">
<div class="gmail_quote">

$body='
Give me advance warning so I can ta=
ke the day off.<br><br><div class=3D"gmail_quote">On Mon, Jan 2, 2012 at 12=
:39 AM
';


$body='
Give me advance warning so I can ta=
ke the day off.<br><br><div class="gmail_quote">On Mon, Jan 2, 2012 at 12=
:39 AM
';


$string = '<div class=3D"gmail_quote">';
$pattern = preg_quote($string, "#"); #escape special characters, and the # character for use as the delimiter
$new_body = preg_replace("#^(.*?){$pattern}.*#s", "$1", $body);

print $new_body;

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Question by:rgb192
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2 Comments
 
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Accepted Solution

by:
Terry Woods earned 2000 total points
ID: 38861302
$pattern = '<div class=(3D)?"gmail_quote">';
$new_body = preg_replace("#^(.*?){$pattern}.*#s", "$1", $body);

print $new_body;

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preg_quote can no longer be used since we don't want the special characters ( and ) and ? to be treated literally. There are no characters that need escaping in the pattern in this case.
0
 

Author Closing Comment

by:rgb192
ID: 38862214
thanks for code and explanation about the characters that do not need to be escaped
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