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excel array formula to create list from another list with wildcard text criteria

Posted on 2013-02-06
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Last Modified: 2013-02-12
I have a row of text values.
Some of these text values end in "95"
I'm trying to build an array formula that will create another list with only those that end in "95.

What I am trying is not working

=INDEX($A$1:$Z$1,0,MATCH("*95",$A$1:$Z$1,0))

any ideas?
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Question by:newparadigmz
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by:barry houdini
ID: 38862084
INDEX/MATCH should work to get the first match (or you can use HLOOKUP with a wildcard too) but you need something more complex to get multiple matches......

If your list is in A1:Z1 then to build another horizontal list of only those values try this formula in A3 confirmed with CTRL+SHIFT+ENTER and copied across

=IFERROR(INDEX($A$1:$Z$1,SMALL(IF(RIGHT($A$1:$Z$1,2)="95",COLUMN($A$1:$Z$1)-COLUMN($A$1)+1),COLUMNS($A3:A3))),"")

If you want a vertical list then replace COLUMNS function at the end with ROWS and drag down like:

=IFERROR(INDEX($A$1:$Z$1,SMALL(IF(RIGHT($A$1:$Z$1,2)="95",COLUMN($A$1:$Z$1)-COLUMN($A$1)+1),ROWS(A$3:A3))),"")

see attached example

regards, barry
multi-lookup.xlsx
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Author Comment

by:newparadigmz
ID: 38865267
Thanks, this works, but is there a way where you dont need to reference the cell the formula is in?

I'd like to be able to put it anywhere and not have to change that reference or use the relative referencing, COLUMNS($A3:A3).

Also, can you explain a little? I don't get why you need small.
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Accepted Solution

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barry houdini earned 500 total points
ID: 38865570
If you want you can use just COLUMN(A1) like

=IFERROR(INDEX($A$1:$Z$1,SMALL(IF(RIGHT($A$1:$Z$1,2)="95",COLUMN($A$1:$Z$1)-COLUMN($A$1)+1),COLUMN(A1))),"")

That should work OK wherever you put it, as long as you are copying across

It doesn't really matter as long as it increments - I use the cell reference of the start cell because it's a little more robust - if you use COLUMN(A1) when starting at E5 that will work but if you now delete column A the A1 reference turns into a #REF! error.

This part of the formula

IF(RIGHT($A$1:$Z$1,2)="95",COLUMN($A$1:$Z$1)-COLUMN($A$1)+1)

returns an array of either FALSE values or the column number of a value ending with 95, i.e. for my example that will return this array

{1,FALSE,FALSE,4,FALSE,FALSE,FALSE,FALSE,9,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE,FALSE}

where 1, 4 and 9 represent the columns where the data ends with 95

and SMALL in conjunction with the COLUMNS function will take the smallest number in the first formula, 2nd smallest in the next, 3rd smallest in the next etc. .....and then INDEX gives you the relevant value from that numbered cell in the range

regards, barry
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