handling dates in vba access 2007

when my users travel, I need to record the time it takes from departure to arrival.
I have all the code to handle this if my users depart and arrive on the same day.  I run into an issue when they depart one day and arrive the following.

if user a departs 10/20/2012 at 23:05 and arrives 10/21/2012 at 11:10 their elapsed time is 12 hours (rounded to nearest quarter hour).  when I try to run this through my code i get a negative result and the program crashes.  How do I handle this type of event?
sptechAsked:
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Kelvin SparksConnect With a Mentor Commented:
You need to calculate the difference between the two in the smallest denominator that your using (minutes I suspect) - probably using the datediff function and then convert to hours.


Kelvin
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sptechAuthor Commented:
that is what I suspected and that is what I coded.  It works.  Nice to have an expert reaffirm my newbie thoughts.
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Scott McDaniel (Microsoft Access MVP - EE MVE )Infotrakker SoftwareCommented:
In addition to Kelvin's suggestion:

Here's info on DateDiff:

http://office.microsoft.com/en-us/access-help/datediff-function-HA001228811.aspx

And here's a good resource with lots of examples:

http://office.microsoft.com/en-us/access-help/calculate-the-difference-between-two-date-or-time-values-HP001098486.aspx

Essentially you'd do something like this:

DateDiff ("n", YourFirstDate, YourLastDate)

That would give the number of Minutes between the two. Obviously you could divide by 60 to get hours.

When supplying the dates be sure they're formed correctly. Access expects them to be in a form like:

01/01/2012 12:30:00

Would represent 30 minutes after Noon on Jan 1 of 2012.

01/01/2010 00:30:00

Would represent 30 minutes after Midnight on Jan 1 of 2012

Access will generally accept most formats, but the more explicit you are with your Dates, the more reliable these functions will be.
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