Find files through command line

I am not aware of any DOS utility out there which will let you do file search and export only file name and path.

You have to open Command Prompt and Type following command

In order to finds all tmp files including subdirectories and pauses display by page.

I use the dir command

dir *.tmp /s /p

and you can export your result to a text file which then you can manupulate the output in excel to show only filename and path

dir *.tmp /s /p > "C:\Users\UserNAME\Desktop\Results.txt"

Thank you. That is what I normally do right now, except I do not user /P and I use /B in order to get the basic output, which gives me the path. This is very close to what I want, but I would also like to have the path and filename in separate values. I will leave this open for a while to see if there is anything else. If not, this is still a great answer. Thanks.

Great!, Below you will find all the attributes you can use with the above command I posted

/A          Displays files with specified attributes.
  attributes   D  Directories                R  Read-only files
               H  Hidden files               A  Files ready for archiving
               S  System files               I  Not content indexed files
               L  Reparse Points             -  Prefix meaning not
  /B          Uses bare format (no heading information or summary).
  /C          Display the thousand separator in file sizes.  This is the
              default.  Use /-C to disable display of separator.
  /D          Same as wide but files are list sorted by column.
  /L          Uses lowercase.
  /N          New long list format where filenames are on the far right.
  /O          List by files in sorted order.
  sortorder    N  By name (alphabetic)       S  By size (smallest first)
               E  By extension (alphabetic)  D  By date/time (oldest first)
               G  Group directories first    -  Prefix to reverse order
  /P          Pauses after each screenful of information.
  /Q          Display the owner of the file.
  /R          Display alternate data streams of the file.
  /S          Displays files in specified directory and all subdirectories.
  /T          Controls which time field displayed or used for sorting
  timefield   C  Creation
              A  Last Access
              W  Last Written
  /W          Uses wide list format.
  /X          This displays the short names generated for non-8dot3 file
              names.  The format is that of /N with the short name inserted
              before the long name. If no short name is present, blanks are
              displayed in its place.
  /4          Displays four-digit years

Thanks. I can get the switches just by using DIR /? at the command prompt.

Hi oBdA, this is exactly what I was looking for, and it works perfectly.

Just saw your VB script question, so for the sake of completeness: if you want the extension separately, just replace "%~nxa" with "%~na,%~xa":
(for /r "C:\Temp" %a in (*.doc) do @echo %~dpa,%~na,%~xa)>test.csv

Thanks, I posted that question before your response.

I tested this by searching my primary drive for DOC files, and came up with quite a list. Two things came to mind. One, is that there might be files with a comma in the name. So, is it possible to change the delimiter to a semi-colon rather than a comma? Then, I wonder if it is more practical to turn the path into an 8.3 path rather than a long pathname. if so, could that be done in this command?

To change the delimiter, just change the commas in the "echo" part to semicolons:
(for /r "C:\Temp" %a in (*.doc) do @echo %~dpa;%~na;%~xa)>test.csv
To generate a short file name, add a "s" as first character after the "~" (but I wouldn't call it practical):
(for /r "C:\Temp" %a in (*.doc) do @echo %~sdpa;%~sna;%~xa)>test.csv

I must be going blind. I didn't see the comma. Thanks again. This is exactly what I needed.