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Supernet: 192.168.51.0/24 and 192.168.52.0/24

Hi,

Per one of the EE expert, Supernet makes all the hosts within a range of network address belong to a same group (This reduces the entries in the network address table)

A company has 2 subnets: 192.168.51.0/24 and 192.168.52.0/24

Is it possible to Supernet them? If yes, would you please provide the direction a little bit

Thanks,
tjie

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David Akinsanya

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tjie

ASKER

Hi Akinsd,
Thank you for the explanation

I am still a little bit confused; please respond to "per my understanding" whether it is correct or wrong as the followings:

The 192.168.51.0/24 is at downstair

And 192.168.52.0/24 is at upstair

Some (servers, clients, network devices, etc) have to be assigned the IP addresses

Per your explanation,
After Supernetting, the network becomes 192.168.51.0/23

I have a client at downstair (I assigned the IP address 192.168.51.120)
Per my understanding, the details of the TCP/IP setting of this client should be:

+ The IP address: 192.168.51.120
+ The Subnet Mask: 255.255.254.0
+ The Gateway: 192.168.51.1
+ The DNS1: 192.168.51.8
+The DNS2: 192.168.51.14

I also have a client at Upstair (I assigned the IP address ¿ 192.168.52.150)
Per my understanding, The details of the TCP/IP setting of this client should be:

+ The IP address: 192.168.52.150
+ The Subnet Mask: 255.255.254.0
+The Gateway: 192.168.52.1
+ The DNS1: 192.168.51.8
+ The DNS2: 192.168.51.14

Do you think "my understanding" is correct or wrong or need to be corrected?
Please provide the direction if it is wrong

Thanks,
tjie

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rochey2009

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SeeMeShakinMyHead

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tjie

ASKER

Hi Rochey2009 & SeeMeShakinMyHead,

Yes, I agree with the recommended approaches from Rochey2009
The correct ones are:

Downstair: 192.168.50.0
Upstair: 192.168.51.0

I need a Confirmation from both you whether “my understanding” (related to the assigned IP addresses to clients either “downstair” or “upstair” are correct or wrong); It is as the followings:

Per Rochey2009’s explanation,
After Supernetting, the network becomes 192.168.50.0/23

I have a client at downstair (I assigned the IP address 192.168.50.120)
Per my understanding, the details of the TCP/IP setting of this client should be:

+ The IP address: 192.168.50.120
+ The Subnet Mask: 255.255.254.0
+ The Gateway: 192.168.50.1
+ The DNS1: 192.168.50.8
+The DNS2: 192.168.50.14

I also have a client at Upstair (I assigned the IP address ; 192.168.51.150)
Per my understanding, The details of the TCP/IP setting of this client should be:

+ The IP address: 192.168.51.150
+ The Subnet Mask: 255.255.254.0
+The Gateway: 192.168.51.1
+ The DNS1: 192.168.50.8
+ The DNS2: 192.168.50.14

Do you think "my understanding" is correct or wrong or need to be corrected?
Please provide the direction if it is wrong

Thank you

tjie

SOLUTION

David Akinsanya

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SOLUTION

David Akinsanya

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