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C# dividing a number into 24 random pieces/shares

Posted on 2013-05-12
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Last Modified: 2013-05-12
Hey guys,

I'm trying to figure out the easiest way to divide a number into 24 parts, but completely random.

For example, if the number is 15,500 how would I be able to divide it up randomly into 24 parts like this:

1. 253
2. 442
3. 101
4. 788
5. 2,232
etc....

The sum of these 24 random pieces should = 15,500.

Any thoughts?
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Question by:mcainc
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4 Comments
 
LVL 42

Expert Comment

by:sedgwick
ID: 39159309
should they all be different?
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Author Comment

by:mcainc
ID: 39159314
yeah, all 24 pieces should be different random numbers that all add up to the desired larger number
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LVL 42

Accepted Solution

by:
sedgwick earned 500 total points
ID: 39159322
here it is:
        static Random rand = new Random();
        public static IEnumerable<int> Split(Int32 val, int parts)
        {
            int left = val;
            for (int i = 0; i < parts - 1; i++)
            {
                var curr = rand.Next(1, left / parts);
                yield return curr;
                left -= curr;
            }
            yield return left;
        }


        static void Main(string[] args)
        {
            Int32 val = 15500;
            var res = Split(val, 24);
            int sum = 0;
            foreach (var item in res)
            {
                Console.WriteLine(item);
                sum += item;
            }
            var match = (sum == val);

        }

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Author Closing Comment

by:mcainc
ID: 39159415
nice!!! thanks
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