Solved

query trouble (MS Access)

Posted on 2013-05-15
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Last Modified: 2013-05-15
I have a table with three fields OpenDt, Serno, and WONumber.  I need to select only the most recent record (OpenDt) for each Serno, while still displaying all three fields.

sample data:
OpenDt        04/23/2013
Serno           1231565483
WONumber 123456
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Question by:drelinger
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6 Comments
 
LVL 61

Accepted Solution

by:
mbizup earned 500 total points
ID: 39167964
Try this -
SELECT t.OpenDt, t.Serno,t.WONumber
FROM YourTable t
INNER JOIN
(
SELECT SerNo, Max(OpenDt) AS MaxDT
FROM YourTable
GROUP BY SerNo
) q
ON t.SerNo = q.SerNo AND t.OpenDT = q.MaxDT

Open in new window

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Expert Comment

by:pjevin
ID: 39168004
Make sure OpenDt is a date field and not a string when doing the above or it will give you the max alphabetically (which would meant 2/1/2013 is less than 10/1/2013).  You could also convert it to a date in the query but it would be much more efficient to have the date stored as a string.
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LVL 92

Expert Comment

by:Patrick Matthews
ID: 39168070
pjevin,

You could also convert it to a date in the query but it would be much more efficient to have the date stored as a string.

I presume you meant to say, "...it would be much more efficient to have the date stored as a date", no?

There is no performance advantage to storing dates as strings, and there are numerous deleterious effects of doing so.

Patrick
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Author Closing Comment

by:drelinger
ID: 39168075
worked perfectly. thank you for the help.
0
 
LVL 3

Expert Comment

by:pjevin
ID: 39168140
Sorry I typed that too fast, yes, store it as a date, not a a string, heh.
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Expert Comment

by:Patrick Matthews
ID: 39168817
:)
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