Manipulate dates in DOS Bat file

I need to write a 'bat' file that

- gets the current date
- Calculates the date of the previous Monday
- Calculates the date of a week from the current Sunday

For example the current date is 5/16 so the previous Monday value would be 5/13 and the week from Sunday value would be 5/26.

Then build a string that includes the date range in the format:

Gary AntonellisSenior Application ConsultantAsked:
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Bill PrewConnect With a Mentor Commented:
Okay, this does what you asked, unless you haven't been clear about all the details.

@echo off

REM Get todays date in julian
call :jdate jToday

REM Calculate what weekday this is (Monday=0)
set /a DOW=(jToday%%7)

REM Calculate prior Monday
set Offset=%DOW%
if %Offset% EQU 0 set Offset=7
set /a jPriorMonday=jToday-%Offset%
call :jdate2date %jPriorMonday% yyyy mm dd
set PriorMonday=%mm%/%dd%/%yyyy%

REM Calculate second next Sunday
set /a Offset=13-%DOW%
set /a jSecondSunday=jToday+%Offset%
call :jdate2date %jSecondSunday% yyyy mm dd
set SecondSunday=%mm%/%dd%/%yyyy%

REM Build and display range
set DateRange=%PriorMonday%_%SecondSunday%
echo %DateRange%

exit /b

REM Subroutines
:jdate JD DateStr -- converts a date string to julian day number with respect to regional date format
::                -- JD      [out,opt] - julian days
::                -- DateStr [in,opt]  - date string, e.g. "03/31/2006" or "Fri 03/31/2006" or "31.3.2006"
:$created 20060101 :$changed 20090328 :$categories DateAndTime
set DateStr=%~2&if "%~2"=="" set DateStr=%date%
for /f "skip=1 tokens=2-4 delims=(-)" %%a in ('"echo.|date"') do (
    for /f "tokens=1-3 delims=/.- " %%A in ("%DateStr:* =%") do (
        set %%a=%%A&set %%b=%%B&set %%c=%%C))
set /a "yy=10000%yy% %%10000,mm=100%mm% %% 100,dd=100%dd% %% 100"
if %yy% LSS 100 set /a yy+=2000 &rem Adds 2000 to two digit years
set /a JD=dd-32075+1461*(yy+4800+(mm-14)/12)/4+367*(mm-2-(mm-14)/12*12)/12-3*((yy+4900+(mm-14)/12)/100)/4
ENDLOCAL & IF "%~1" NEQ "" (SET %~1=%JD%) ELSE (echo.%JD%)

:jdate2date JD YYYY MM DD -- converts julian days to gregorian date format
::                     -- JD   [in]  - julian days
::                     -- YYYY [out] - gregorian year, i.e. 2006
::                     -- MM   [out] - gregorian month, i.e. 12 for december
::                     -- DD   [out] - gregorian day, i.e. 31
:$created 20060101 :$changed 20080219 :$categories DateAndTime
set /a L= %~1+68569,     N= 4*L/146097, L= L-(146097*N+3)/4, I= 4000*(L+1)/1461001
set /a L= L-1461*I/4+31, J= 80*L/2447,  K= L-2447*J/80,      L= J/11
set /a J= J+2-12*L,      I= 100*(N-49)+I+L
set /a YYYY= I,  MM=100+J,  DD=100+K
set MM=%MM:~-2%
set DD=%DD:~-2%
    IF "%~2" NEQ "" (SET %~2=%YYYY%) ELSE echo.%YYYY%
    IF "%~3" NEQ "" (SET %~3=%MM%) ELSE echo.%MM%
    IF "%~4" NEQ "" (SET %~4=%DD%) ELSE echo.%DD%

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Bill PrewCommented:
Does this have to be pure batch, or could a solution that used a small utility (EXE) or a small helper script (VBS) be okay?

Also, if the current day is either Monday, or Sunday could you clarify what day you want calculated in those two "boundary conditions"?

Steve KnightIT ConsultancyCommented:
Was going to respond with VBScript suggestion but will leave you with Bill...

Gary AntonellisSenior Application ConsultantAuthor Commented:
I have not had a chance to test it but it looks like it will work.  If you don't mind I will contact you if there is a problem.

Bill PrewCommented:
Sure, let me know how you make out.

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