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need help with query

Hi experts,
I have a situation where I should find customers who have a deleted flag 'D' and blank ' ' for the same email address. Please find below example:

customer_no  | emailAddress  | Deleted
 1111                ap@gmail.com       D
 2221                bp@gmail.com       D
 1111                ap@gmail.com      
 3333                cp@gmail.com
0
sqlcurious
Asked:
sqlcurious
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3 Solutions
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Give this a whirl...

SELECT DISTINCT yt1.customer_no, yt1.emailAddress
FROM YourTable yt1
WHERE Deleted = 'D'
JOIN (
   SELECT DISTINCT customer_no, emailAddress
   FROM YourTable
   WHERE Deleted = '') yt2 ON yt1.customer_no = yt2.customer_no AND yt1.email_address = yt2.email_address
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Surendra NathTechnology LeadCommented:
check this out

selecet * from YourTable
where Delted = 'D'
AND emailAddress  = ''

Open in new window

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PortletPaulfreelancerCommented:
Although you asked for the reverse of what I'm suggesting here, I assume you are trying to find the records without the 'D' so they are either removed or to have the Deleted field set to 'D'. If this is the case then this is similar to Jim's suggestion but with a couple of tweaks. The inner subquery finds those records with Deleted = 'D' so that the final result is of those records of Deleted = ''. And; the where clause is moved under the from clause.
SELECT
      c1.customer_no
    , c1.emailAddress
FROM Customers c1
INNER JOIN (
            SELECT DISTINCT
                  customer_no
                , emailAddress
            FROM Customers
            WHERE Deleted = 'D'
            ) c2 ON c1.customer_no = c2.customer_no
                    AND c1.email_address = c2.email_address
WHERE c1.Deleted = ''
    -- or c1.Deleted is null

Open in new window

although you only asked for '' in the filtering I'd suggest you also look for nulls in the Deleted field.
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SharathData EngineerCommented:
try this.
SELECT customer_no, 
       emailAddress 
  FROM test 
 WHERE Deleted IN ( '', 'D' ) 
 GROUP BY customer_no, 
          emailAddress 
HAVING COUNT(*) = 2 
       AND MIN(Deleted) = '' 
       AND MAX(Deleted) = 'D' 

Open in new window


see the example here: http://sqlfiddle.com/#!3/e1153/2
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Scott PletcherSenior DBACommented:
SELECT
    emailAddress,
    MIN(customer_no) AS minCustomer,
    MAX(customer_no) AS maxCustomer
FROM
    dbo.tablename
WHERE
    Deleted IN ( '', 'D' )
GROUP BY
    emailAddress
HAVING
    MIN(Deleted) = '' AND
    MAX(Deleted) = 'D'
ORDER BY
    emailAddress
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sqlcuriousAuthor Commented:
For some reason none of the queries above are working :( any idea as to what's going on?
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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Define 'not working'.  Is there an error message?  No return records?  
Does the 'deleted flag' and email address values have any trailing spaces?
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PortletPaulfreelancerCommented:
"not working" does not give us much to work with and it would be good to know what the symptoms really are. Perhaps try the following and provide the results?
SELECT 'c1.Deleted ""' AS filterfor
	, count(*) AS counted
FROM Customers c1
WHERE c1.Deleted = ''

UNION ALL

SELECT 'c1.Deleted "" or null' AS filterfor
	, count(*) AS counted
FROM Customers c1
WHERE c1.Deleted = ''
	OR c1.Deleted IS NULL

UNION ALL

SELECT 'c1.Deleted not "D" or null' AS filterfor
	, count(*) AS counted
FROM Customers c1
WHERE c1.Deleted NOT = 'D'
	OR c1.Deleted IS NULL

UNION ALL

SELECT 'Deleted = "D"' AS filterfor
	, count(*) AS counted
FROM Customers
WHERE Deleted = 'D'

UNION ALL

SELECT DISTINCT 'Deleted like "D%"' AS filterfor
	, count(*) AS counted
FROM Customers
WHERE Deleted LIKE 'D%';

Open in new window

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sqlcuriousAuthor Commented:
Hi all, I am sorry about not being specific, @Jimhorn I wasnt getting any results.
@PortletPaul please find the results below for the query you suggested:

filterfor                       Counted
c1.Deleted ""      1752036
c1.Deleted "" or null      1752036
c1.Deleted not "D" or null      1752037
Deleted = "D"      1734839
Deleted like "D%"      1734839

Pls suggest, thanks
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PortletPaulfreelancerCommented:
sqlcurious, thanks very much for the results. they show that the data is very much as you explain it - so I'm really not sure why you are not get results from any of the queries.

did you try the one from Scott? (ID: 39181904) using an aggregation may be just the ticket.
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sqlcuriousAuthor Commented:
yes Scott's worked, guess I was doing something wrong with the group by earlier, thanks !
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sqlcuriousAuthor Commented:
Thanks!
0
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