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xml winforms viewer

Posted on 2013-05-17
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Last Modified: 2013-05-22
I have a win form c# application that uses web services.  I am outputting the xml into a text area, but it isn't too readable.  Does anyone know of some control that I can use to view the xml better?  I can open it in internet explorer if i save it to a file, but I am not sure in C#.  I found a post, but the link for files was down.  This isn't huge for me, so I don't want to spend a ton of time.  i was hoping for something easy and pre-built.

Thanks!
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Question by:jackjohnson44
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LVL 42

Assisted Solution

by:Meir Rivkin
Meir Rivkin earned 2000 total points
ID: 39176723
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jackjohnson44 earned 0 total points
ID: 39176771
I used the second link, then the second answer on that page.  Basically it creates a tree view control and sets its source to an xml string.  It was a little difficult because it was a console app that just opened.

Its easy to use.  You just need two functions.  In this example "treeXml" is a TreeView added to the page.

just call: SetTreeViewSourceToXml(xmlSource);

        private void SetTreeViewSourceToXml(string xmlSource)
        {
            treeXml.Nodes.Clear();
            XmlDocument doc = new XmlDocument();
            try
            {
                doc.LoadXml(xmlSource);
            }
            catch (Exception err)
            {
                MessageBox.Show(err.Message);
                return;
            }

            ConvertXmlNodeToTreeNode(doc, treeXml.Nodes);
            treeXml.Nodes[0].ExpandAll();
        }

        private void ConvertXmlNodeToTreeNode(XmlNode xmlNode, TreeNodeCollection treeNodes)
        {
            TreeNode newTreeNode = treeNodes.Add(xmlNode.Name);

            switch (xmlNode.NodeType)
            {
                case XmlNodeType.ProcessingInstruction:
                case XmlNodeType.XmlDeclaration:
                    newTreeNode.Text = "<?" + xmlNode.Name + " " +
                                       xmlNode.Value + "?>";
                    break;
                case XmlNodeType.Element:
                    newTreeNode.Text = "<" + xmlNode.Name + ">";
                    break;
                case XmlNodeType.Attribute:
                    newTreeNode.Text = "ATTRIBUTE: " + xmlNode.Name;
                    break;
                case XmlNodeType.Text:
                case XmlNodeType.CDATA:
                    newTreeNode.Text = xmlNode.Value;
                    break;
                case XmlNodeType.Comment:
                    newTreeNode.Text = "<!--" + xmlNode.Value + "-->";
                    break;
            }

            if (xmlNode.Attributes != null)
            {
                foreach (XmlAttribute attribute in xmlNode.Attributes)
                {
                    ConvertXmlNodeToTreeNode(attribute, newTreeNode.Nodes);
                }
            }
            foreach (XmlNode childNode in xmlNode.ChildNodes)
            {
                ConvertXmlNodeToTreeNode(childNode, newTreeNode.Nodes);
            }
        }

    }
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LVL 42

Expert Comment

by:Meir Rivkin
ID: 39176772
so did u manage to run it?
do u need any further help?
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Author Comment

by:jackjohnson44
ID: 39176791
I'm good thanks.  That works great.  My code above will work.   I only marked that as the answer so people would see it.  I gave you the points.

Thanks and have a good weekend!!
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Author Closing Comment

by:jackjohnson44
ID: 39186901
Thanks a lot! I want people to read my answer because it will save a lot of time.  The link was helpful but was geared toward a console app.
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