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# Next and previous day SQL

Posted on 2013-05-21
Medium Priority
466 Views
I need some DB2 SQL help identifying accounts that had restrictions removed the previous day, then placed again the next day. Example below:

ACCT_NUM      START_DT               END_DT
10019220      02-28-2013      04-08-2013
10019220      04-09-2013      04-29-2013

The restriction end_dt is 4/8/2013, and the next day (start_dt 4/9/2013), it was placed on the account.
What date function/code snippet do I use to identify only this scenario above?

Thank you.
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Question by:saved4use
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LVL 37

Assisted Solution

momi_sabag earned 80 total points
ID: 39185052
try

select t1.acct_num
from your_table t1
join your_table t2
on t1.acct_num = t2.acct_num and t1.end_dt = t2.end_dt - 1 day
0

LVL 32

Accepted Solution

awking00 earned 1920 total points
ID: 39185237
What version of DB2? I believe with 9.5 you have the lead/lag functions available. If so,

select acct_num start_dt, end_dt from
(select acct_num start_dt, end_dt,
lead(start_dt) over (partition by acct_num order by start_dt) as nextdt
from yourtable) x
where days(nextdt) - days(end_dt) <= 1;
In your example, this would retrieve
10019220      02-28-2013      04-08-2013
If you wanted
10019220      04-09-2013      04-29-2013
select acct_num start_dt, end_dt from
(select acct_num start_dt, end_dt,
lag(end_dt) over (partition by acct_num order by start_dt) as prevdt
from yourtable) x
where days(start) - days(prevdt) <= 1;
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