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VB.Net -  Issue with random number being written to text file

Posted on 2013-05-21
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Last Modified: 2013-05-21
Good Morning,

I am using Visual Studio Express 2012 for a windows form with VB.Net.

My code below basically works for its intended purpose, which is, depending on what the user selects on the form will be written in a text file.

Final result of the text file looks like this:

\\ServerA\input\sobi\05172013040604\16624-20130206-FTO-1.pdf|16624|_||TestDG|TestDT|TestDST|250|05/07/2013|
\\ServerA\input\sobi\05172013040604\16624-20130206-FTO-2.pdf|16624|_||TestDG|TestDT|TestDST|250|05/07/2013|
\\ServerA\input\sobi\05172013040604\16624-20130206-FTO-3.pdf|16624|_||TestDG|TestDT|TestDST|250|05/07/2013|

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My issue is that my random number when generated is not as random as I would like it. As you can see from the example above the random number is “250” for all of the lines of the output. When each line should have a different random number example below:

\\ServerA\input\sobi\05172013040604\16624-20130206-FTO-1.pdf|16624|_||TestDG|TestDT|TestDST|340|05/07/2013|
\\ServerA\input\sobi\05172013040604\16624-20130206-FTO-2.pdf|16624|_||TestDG|TestDT|TestDST|854|05/07/2013|
\\ServerA\input\sobi\05172013040604\16624-20130206-FTO-3.pdf|16624|_||TestDG|TestDT|TestDST|188|05/07/2013|

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I’m thinking the reason the random number is all the same for each line is because my code is creating the output all at one go and this is why each line is using the same random number.

I’m fairly new to VB.Net, would someone be able to tell me how or what code I am to use to ensure each line written to the text file has a different random number?

Part of my code is below.

        'Define random number for comment field of each file

        Dim randomclass As New System.Random()
        Dim randomnumber As Integer
        randomnumber = randomclass.Next(100, 999)

        BackgroundWorker1.ReportProgress(50)

        'create txt file from dest directory of all files to be indexed.

        Dim str As String
        For Each rfiles As String In System.IO.Directory.GetFiles(destdir)
            str = str & rfiles & "|" & System.IO.Path.GetFileNameWithoutExtension(rfiles).Split("-")(0).Trim & "|" & "_" & "||" & DataGridView1.SelectedRows(0).Cells(0).Value & "|" & DataGridView1.SelectedRows(0).Cells(1).Value & "|" & DataGridView1.SelectedRows(0).Cells(2).Value & "|" & randomnumber & "|" & DateTimePicker1.Text & "|" & Environment.NewLine
        Next

        Dim outputname As String = [String].Format("\\ServerA\input\sobi{0}.txt", DateTime.Now.ToString("MMddyyyyhhmmss"))
        System.IO.File.WriteAllText(outputname, str)

        BackgroundWorker1.ReportProgress(65)

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Kindly advise,

Regards,
N
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Comment
Question by:nobushi
3 Comments
 
LVL 11

Expert Comment

by:apathy42
ID: 39184953
Check this thread out, I believe the comment on this matches what you're looking for:

http://stackoverflow.com/questions/18676/random-int-in-vb-net
0
 
LVL 14

Accepted Solution

by:
quizwedge earned 500 total points
ID: 39184969
Move randomnumber = randomclass.Next(100, 999) to inside the for each loop

   'Define random number for comment field of each file

        Dim randomclass As New System.Random()
        Dim randomnumber As Integer

        BackgroundWorker1.ReportProgress(50)

        'create txt file from dest directory of all files to be indexed.

        Dim str As String
        For Each rfiles As String In System.IO.Directory.GetFiles(destdir)
            randomnumber = randomclass.Next(100, 999)
            str = str & rfiles & "|" & System.IO.Path.GetFileNameWithoutExtension(rfiles).Split("-")(0).Trim & "|" & "_" & "||" & DataGridView1.SelectedRows(0).Cells(0).Value & "|" & DataGridView1.SelectedRows(0).Cells(1).Value & "|" & DataGridView1.SelectedRows(0).Cells(2).Value & "|" & randomnumber & "|" & DateTimePicker1.Text & "|" & Environment.NewLine
        Next

        Dim outputname As String = [String].Format("\\ServerA\input\sobi{0}.txt", DateTime.Now.ToString("MMddyyyyhhmmss"))
        System.IO.File.WriteAllText(outputname, str)

        BackgroundWorker1.ReportProgress(65)

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0
 
LVL 1

Author Closing Comment

by:nobushi
ID: 39185076
Thank you.
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