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How to show latest date in Access 2010?

Posted on 2013-05-22
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Last Modified: 2013-06-02
Hi Everyone,

I have a query that is complex and runs great.  The query displays the results from a cash payment table for individual customers.  If a customer as 12 rows of payments (one for each month of the year), then all 12 show up in the result of the query.  What I want is the latest paydate to show up.  When I try to do the Group By, and elect my PAY_DATE field, it doesn't work.

Any suggestions?
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Question by:Anthony6890
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18 Comments
 
LVL 48

Expert Comment

by:Dale Fye (Access MVP)
ID: 39187508
not enough detail here to provide much help?

What does the query look like that "runs great".  What have you tried for this new query?

"What I want is the latest paydate to show up."

show up where?  do you want this as a separate row in the query results?
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LVL 1

Author Comment

by:Anthony6890
ID: 39187536
Sorry about the lack of detail.  

The query has three tables linked that pull values from each table based on one value being in the first table.  The query provides these results:

Customer Name
Pay Date
Pay Amount
Old Store
New Store

If the customer name has payments for a year, I will have 12 rows for one person with the the Pay Date changing and potentially the Pay Amount changing (but this change is not applicable to the application).  

When I run the query I want the result to just have the latest pay date row display as the result.  So if someone has paid from 1/1/2013-5/1/2013, I just want the 5/1/2013 row to be displayed.
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LVL 50

Expert Comment

by:Gustav Brock
ID: 39187622
You will Group By Customer_Name (not Pay_Date) and select this additional column:

LatestPayDate: Max([Pay_Date])

/gustav
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LVL 35

Expert Comment

by:[ fanpages ]
ID: 39187635
Hi,

Try adding a WHERE clause on your existing SQL statement (query) something like this:

WHERE Month([Pay Date])=Month(Now())

...or, if still using a GROUP BY clause, use:

HAVING Month([Pay Date])=Month(Now())

BFN,

fp.
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Author Comment

by:Anthony6890
ID: 39187650
Gustav,

Is this expression:  LatestPayDate: Max([Pay_Date])

a Total:  Group By?


Fp, I can't guarantee that the customer will have a payment for this month, it could also be that the latest payment is from 3 months ago... will your idea still work?
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LVL 35

Expert Comment

by:[ fanpages ]
ID: 39187680
Fp, I can't guarantee that the customer will have a payment for this month, it could also be that the latest payment is from 3 months ago... will your idea still work?

No, sorry.

The MAX([Pay_Date]) for the Customer is the way to go in that case.
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LVL 50

Expert Comment

by:Gustav Brock
ID: 39187729
> will your idea still work?

Yes. Try it. Takes two minutes or so.

/gustav
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LVL 1

Author Comment

by:Anthony6890
ID: 39187819
I'm having a problem entering this:

HAVING Month([Pay Date])=Month(Now())

I'm still using GROUP BY.

Where do I enter this line?
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LVL 50

Expert Comment

by:Gustav Brock
ID: 39187856
Why don't you use the GUI Query designer? Then you can switch back and forth between this and the SQL code  ... and experiment and learn at the same time. Much easier.

/gustav
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LVL 1

Author Comment

by:Anthony6890
ID: 39187861
Agreed Gustav, I will try that.  thanks.
0
 
LVL 1

Author Comment

by:Anthony6890
ID: 39187869
Gustav, there is something that might be a problem.  

My PAY_DATE field is an expression...

PAY_DATE: DateSerial(Mid([BCPDTE] & "01",2,2),Mid([BCPDTE] & "01",4,2),Mid([BCPDTE] & "01",6,2))

Does this complicate things.
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LVL 35

Expert Comment

by:[ fanpages ]
ID: 39187893
Anthony6890: It may make everybody's task easier if you post the entire SQL statement you are using.

We can then advise exactly what is required.

Thanks.
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LVL 50

Expert Comment

by:Gustav Brock
ID: 39187895
Yes, if the Query asks for parameter Pay_Date, you may need to use:

LatestPayDate: Max(DateSerial(Mid([BCPDTE] & "01",2,2),Mid([BCPDTE] & "01",4,2),Mid([BCPDTE] & "01",6,2)))

Is BCPDTE a string?

/gustav
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LVL 48

Expert Comment

by:Dale Fye (Access MVP)
ID: 39187929
I'm trying to determine the purpose of adding the "01" onto the end of field [BCPDTE].

Can you provide some examples of the values in that field and explain why you think you need to add the "01"?
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Author Comment

by:Anthony6890
ID: 39187971
Ok, here is the entire SQL...

SELECT BILMAC_MBRLOG.[MLSS#], BILMAC_MBRLOG.MLFILE, BILMAC_MBRLOG.MLFLD, BILMAC_MBRLOG.MLOLCO, BILMAC_MBRLOG.MLNUCO, CDate(IIf(Len([MLCHDT])=7,Format(Mid([MLCHDT],4,2) & "-" & Mid([MLCHDT],6,2) & "-" & Mid([MLCHDT],2,2),"mm/dd/yyyy"),Format(Mid([MLCHDT],3,2) & "-" & Mid([MLCHDT],5,2) & "-" & Left([MLCHDT],2),"mm/dd/yyyy"))) AS CHANGE_DATE, CDate(IIf(Len([MBHIRE])=7,Format(Mid([MBHIRE],4,2) & "-" & Mid([MBHIRE],6,2) & "-" & Mid([MBHIRE],2,2),"mm/dd/yyyy"),Format(Mid([MBHIRE],3,2) & "-" & Mid([MBHIRE],5,2) & "-" & Left([MBHIRE],2),"mm/dd/yyyy"))) AS HIRE_DATE, CDate(IIf(Len([MBELDT])=7,Format(Mid([MBELDT],4,2) & "-" & Mid([MBELDT],6,2) & "-" & Mid([MBELDT],2,2),"mm/dd/yyyy"),Format(Mid([MBELDT],3,2) & "-" & Mid([MBELDT],5,2) & "-" & Left([MBELDT],2),"mm/dd/yyyy"))) AS ELIG_DATE, LBSI_BCHCSHHC.BCAMT2, DateSerial(Mid([BCPDTE] & "01",2,2),Mid([BCPDTE] & "01",4,2),Mid([BCPDTE] & "01",6,2)) AS PAY_DATE
FROM (BILMAC_MBRLOG LEFT JOIN BILMAC_MBRMSTR ON BILMAC_MBRLOG.[MLSS#] = BILMAC_MBRMSTR.[MBSS#]) LEFT JOIN LBSI_BCHCSHHC ON BILMAC_MBRLOG.[MLSS#] = LBSI_BCHCSHHC.[BCSS#]
WHERE (((BILMAC_MBRLOG.[MLSS#])<>123456789) AND ((BILMAC_MBRLOG.MLFILE)="MBRMST") AND ((BILMAC_MBRLOG.MLFLD)="MBSTOR") AND ((BILMAC_MBRLOG.MLOLCO)<>"000000" And (BILMAC_MBRLOG.MLOLCO)<>"000" And (BILMAC_MBRLOG.MLOLCO)<>"") AND ((BILMAC_MBRLOG.MLNUCO)<>"002" And (BILMAC_MBRLOG.MLNUCO) Not Like "0000*") AND ((Left([MLOLCO],3))<>Left([MLNUCO],3)) AND ((BILMAC_MBRLOG.MLCHDT)>=[Forms]![RUNDTEf].[CONVERTED_START] And (BILMAC_MBRLOG.MLCHDT)<=[Forms]![RUNDTEf].[CONVERTED_END]) AND ((BILMAC_MBRMSTR.MBSTUS)="A") AND ((LBSI_BCHCSHHC.BCTYPE)="P"))
ORDER BY BILMAC_MBRLOG.[MLSS#];

Open in new window


The values in BCPDTE are:  10304 (CYYMM)

Pay Date isn't a variable, it's simply just an expression field converting a CYYMM date from an iseries into a date value.
0
 
LVL 35

Expert Comment

by:[ fanpages ]
ID: 39188051
To save anybody else the hassle of re-formatting the SQL statement into something (semi-)legible:

SELECT
BILMAC_MBRLOG.[MLSS#],
BILMAC_MBRLOG.MLFILE,
BILMAC_MBRLOG.MLFLD,
BILMAC_MBRLOG.MLOLCO,
BILMAC_MBRLOG.MLNUCO,

CDate(IIf(Len([MLCHDT])=7,
	  Format(Mid([MLCHDT],4,2) & "-" & Mid([MLCHDT],6,2) & "-" & Mid([MLCHDT],2,2),"mm/dd/yyyy"),
	  Format(Mid([MLCHDT],3,2) & "-" & Mid([MLCHDT],5,2) & "-" & Left([MLCHDT],2),"mm/dd/yyyy")
	 )
     ) AS CHANGE_DATE,

CDate(IIf(Len([MBHIRE])=7,
          Format(Mid([MBHIRE],4,2) & "-" & Mid([MBHIRE],6,2) & "-" & Mid([MBHIRE],2,2),"mm/dd/yyyy"),
	  Format(Mid([MBHIRE],3,2) & "-" & Mid([MBHIRE],5,2) & "-" & Left([MBHIRE],2),"mm/dd/yyyy")
         )
     ) AS HIRE_DATE,

CDate(IIf(Len([MBELDT])=7,
	  Format(Mid([MBELDT],4,2) & "-" & Mid([MBELDT],6,2) & "-" & Mid([MBELDT],2,2),"mm/dd/yyyy"),
	  Format(Mid([MBELDT],3,2) & "-" & Mid([MBELDT],5,2) & "-" & Left([MBELDT],2),"mm/dd/yyyy")
	 )
     ) AS ELIG_DATE,

LBSI_BCHCSHHC.BCAMT2,

DateSerial(Mid([BCPDTE] & "01",2,2),Mid([BCPDTE] & "01",4,2),Mid([BCPDTE] & "01",6,2)) AS PAY_DATE

FROM
(
	BILMAC_MBRLOG
	LEFT JOIN BILMAC_MBRMSTR
	ON
	BILMAC_MBRLOG.[MLSS#] = BILMAC_MBRMSTR.[MBSS#]
)
LEFT JOIN LBSI_BCHCSHHC
ON
BILMAC_MBRLOG.[MLSS#] = LBSI_BCHCSHHC.[BCSS#]

WHERE
(
	(
		(BILMAC_MBRLOG.[MLSS#])<>123456789
	)
	AND
	(
		(BILMAC_MBRLOG.MLFILE)="MBRMST"
	)
	AND
	(
		(BILMAC_MBRLOG.MLFLD)="MBSTOR"
	)
	AND
	(
		(BILMAC_MBRLOG.MLOLCO)<>"000000"
		And
		(BILMAC_MBRLOG.MLOLCO)<>"000"
		And
		(BILMAC_MBRLOG.MLOLCO)<>""
	)
	AND
	(
		(BILMAC_MBRLOG.MLNUCO)<>"002"
		And
		(BILMAC_MBRLOG.MLNUCO) Not Like "0000*"
	)
	AND
	(
		(Left([MLOLCO],3))<>Left([MLNUCO],3)
	)
	AND
	(
		(BILMAC_MBRLOG.MLCHDT)>=[Forms]![RUNDTEf].[CONVERTED_START]
		And
		(BILMAC_MBRLOG.MLCHDT)<=[Forms]![RUNDTEf].[CONVERTED_END]
	)
	AND
	(
		(BILMAC_MBRMSTR.MBSTUS)="A"
	)
	AND
	(
		(LBSI_BCHCSHHC.BCTYPE)="P"
	)
)
	
ORDER BY
BILMAC_MBRLOG.[MLSS#];

Open in new window

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LVL 1

Accepted Solution

by:
Anthony6890 earned 0 total points
ID: 39201344
I ended up getting this t work by creating two separate queries doing the max of two separate columns in each query and then combining them.  Thanks everyone for your help.
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LVL 1

Author Closing Comment

by:Anthony6890
ID: 39214064
Needed to come up with an alternative way of reaching the max of two fields and was able to figure it out on my own.
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