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insert multiple list box values into MySQL Database using PHP

Posted on 2013-05-22
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Last Modified: 2013-10-17
I can't figure out what is wrong with this code.  It inserts all fields EXCEPT the which_state field.  I've added the brackets [] after the select name, to make it an array, but it's not working.  Thank you!

form field:
<select name="which_state[]" id="which_state[]" size="10" multiple="multiple" class="formMenufield_Medium" tabindex="5">
                            <option value="Colorado">Colorado</option>
                            <option value="Florida">Florida</option>
                            <option value="Illinois">Illinois</option>
                            <option value="Michigan">Michigan</option>
                            <option value="Minnesota">Minnesota</option>
                            <option value="Ohio">Ohio</option>
                            <option value="Texas">Texas</option>
                            <option value="Wisconsin">Wisconsin</option>
</select>

insert script:
if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "SSContact_Sharp_Default")) {
  $insertSQL = sprintf("INSERT INTO emails (email, phone, full_name, which_state) VALUES (%s, %s, %s, %s)",
                       GetSQLValueString($_POST['Email_Address'], "text"),
                       GetSQLValueString($_POST['phone'], "text"),
                       GetSQLValueString($_POST['Full_Name'], "text"),
                       GetSQLValueString($_POST['which_state[]'], "text"));

  mysql_select_db($database_allanb, $allanb);
  $Result1 = mysql_query($insertSQL, $allanb) or die(mysql_error());
0
Comment
Question by:ssailer
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9 Comments
 
LVL 15

Assisted Solution

by:Jagadishwor Dulal
Jagadishwor Dulal earned 333 total points
ID: 39188246
Why are you using [] in $_POST value remove it like:
GetSQLValueString($_POST['which_state'], "text"));

Open in new window

0
 
LVL 15

Assisted Solution

by:Jagadishwor Dulal
Jagadishwor Dulal earned 333 total points
ID: 39188262
Again you are using array in id also it is not necessary. Your select should be:
<select name="which_state[]" id="which_state" size="10" multiple="multiple" class="formMenufield_Medium" tabindex="5">

Open in new window

when you post your form try checking the value first like:

	$which_state= $_POST['which_state'];
	foreach($which_state as $ws){
	 echo $ws."<br/>";
	}

Open in new window

0
 

Author Comment

by:ssailer
ID: 39188419
I can get the selections to output as an array ... it just won't write the values to the database.  

I changed my select statement to this:  <select name="which_state[]" id="which_state" size="10" multiple="multiple" class="formMenufield_Medium" tabindex="5">

Actually, the code above is only outputting the first item selected in the list.
0
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Author Comment

by:ssailer
ID: 39188477
I can get the array to output doing the following:

if (isset($_POST['which_state'])) {
              $ws = $_POST['which_state'];
              foreach ($ws as $wch)
               {
                   echo 'which states '.$wch;
               }
           }


Then, if I change the insert script to this,

if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "SSContact_Sharp_Default")) {
  $insertSQL = sprintf("INSERT INTO emails (email, phone, full_name, which_state) VALUES (%s, %s, %s, %s)",
                       GetSQLValueString($_POST['Email_Address'], "text"),
                       GetSQLValueString($_POST['phone'], "text"),
                       GetSQLValueString($_POST['Full_Name'], "text"),
                       GetSQLValueString($wch, "text"));


I would think that it would insert the array in the which_state field.  It does not.  Although, now it enters ONE of the states from the list, but not all of them.  

I know I'm close, but I just can't figure it out.
0
 
LVL 15

Expert Comment

by:Jagadishwor Dulal
ID: 39188496
That's why I am showing you example of foreach loop above for values:

$which_state= $_POST['which_state'];
	foreach($which_state as $ws){
	 echo $ws."<br/>";
	}

Open in new window

change it to your method
0
 

Author Comment

by:ssailer
ID: 39188519
Finally - I got it to work!  

GetSQLValueString(implode(',', $_POST['which_state']), "text"));
0
 
LVL 83

Accepted Solution

by:
Dave Baldwin earned 167 total points
ID: 39188538
You have to extract the values from the array and put them in a string that can be inserted into the field.  The array name is just a pointer to the data structure.  And I believe that $wch in the foreach is strictly a local variable for the foreach.  If you create a variable outside the foreach and just concatenate $wch to it ($states .= $wch.' ';), then you would have data you could use in the INSERT.
0
 

Author Comment

by:ssailer
ID: 39188552
Actually, I got it working - see my post above.  In the insert script, I used GetSQLValueString(implode...
0
 

Author Closing Comment

by:ssailer
ID: 39580379
resolved it mostly myself.
0

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