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jQuery: Combine Not into First Element Selector

Posted on 2013-05-22
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Last Modified: 2013-05-23
How can this be combined so that the "not" is combined with the first element selector?

$('a[href]').not('[href^="http"],[href^="mailto:"],[href^="/"],[href^="."],[href^="#"]').each(function(ev) { });

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This does not work:

$('a[href]:not([href^="http"],[href^="mailto:"],[href^="/"],[href^="."],[href^="#"])').each(function(ev) {});

Open in new window

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Question by:hankknight
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Accepted Solution

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mickey159 earned 500 total points
ID: 39189767
Additional Notes (from jqAPI)
The .not() method will end up providing you with more readable selections than pushing complex selectors or variables into a :not() selector filter. In most cases, it is a better choice.

I suppose it is better to separate using a .not() as you can read and maintain easily.
Please try this:

$('a:not([href^="http"],[href^="mailto:"],[href^="/"],[href^="."],[href^="#"])').each(function(ev) {});

Open in new window


Please give some more code so I can test the codes.
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