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how to parse string to double upto two decimal digits

Parse string to double returns me the double value upto one decimal digit.
How to get the double value upto two decimal digits. I want it to be 1.00and not 1.0

String Amt = "1.00";
Double Price = Double.parseDouble(Amt);

Ouput:- 1.0
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Newton21205
Asked:
Newton21205
2 Solutions
 
CEHJCommented:
Numbers (double/Double in your case) don't have formats, so you have what is known as a 'category error'. Only strings have formats
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krakatoaCommented:
import java.text.*;
import java.math.*;


class DecFormat {

static DecimalFormat df;
static BigDecimal bd;
static Number num;
static Double d;
static Float dd;

static final double FNUM = 123456.00;




	public static void main(String[] args){


double dub = 12345678.00;
DecimalFormat def = new DecimalFormat();

def.applyPattern("##,###,###.##;(##,###,###.##)");

def.setMinimumFractionDigits(2);

//def.setRoundingMode(RoundingMode.valueOf("HALF_DOWN") );//cant get this to work

System.out.print(def.format(dub));

System.exit(0);
		DecimalFormat f = new DecimalFormat("###########0.00");
		
		df = new DecimalFormat();
		//df = new DecimalFormat();
		//df.setMinimumFractionDigits(2);
				
		//df.applyPattern("##,###,###.00;(##,###,###.00)");
		

				//df.setRoundingMode(RoundingMode.valueOf("UNNECESSARY") );

		//num = df.parse("12345678.00",new ParsePosition(0));
		//num = f.parse("12345678.00",new ParsePosition(0));
num = f.parse("123456.00",new ParsePosition(0));
Float fl = new Float(num.floatValue());				
		System.out.println(fl);
		

	}


}

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CEHJCommented:
String Amt = "1.00";
double d = Double.parseDouble(Amt); // Don't use capitals for variable names in Java
String amt = String.format("%.2f", d);
System.out.println(amt); // But it's now a String again

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Newton21205Author Commented:
@CEHJ : i want a double not a string
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mccarlIT Business Systems Analyst / Software DeveloperCommented:
What CEHJ is saying and trying to point out to you, is that a "double" has NO concept of "number of decimal places", ie. 1.00 = 1.0 = 1.00000000 = etc, etc. It is ONLY when it is converted to a String either explicitly using String.format, etc or implicitly (see below) that the number of decimal places that you want included in the String is important.

What do I mean by "converted implicitly" above? Well, in your original question, the last line says, Output:- 1.0. How did you get to that conclusion? I am assuming that at some point you did something along the lines of, System.out.println(Amt);??? If so, then in that one line, an implicit conversion to a String occurs. It has to because to write to the console, which is just a stream of characters, a number such as Amt needs to be converted to it's textual representation. "System.out" is actually a PrintStream object, and if you follow the trail of Javadoc references for the PrintStream .println(double) method, you will see those references describing this implicit conversion and ending up at Double.toString(double). If you read the description of the method in that Javadoc you will see why it printed "1.0" to the console.


So, what should YOU do then? Well, just use your Double everywhere that you need to representation a decimal number (of any number of decimal places), ie. add it to others, subtract, multiply, divide, whatever you want to do with it. And then AFTER you do all your mathematical operations, and you then want to print the result to the console, that's when you use the last two lines of CEHJ's post to "explicitly" convert the result to a String (that way YOU control the number of decimals included) and then print the String to the console.
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CEHJCommented:
@CEHJ : i want a double not a string
What is the mathematical difference between 1.0 and 1.00? Answer: there isn't one, which is why a number has no need of, and no means of, distinguishing between the two.
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krakatoaCommented:
I posted the wrong code above, so for the record, this is what I meant to post :

String du = "12345678.00";
double dub = new Double(du);//12345678.00;
DecimalFormat def = new DecimalFormat();

def.applyPattern("##,###,###.00;(##,###,###.00)");

System.out.print(def.format(dub));

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