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lower case on last name

Runing the following script to update first and lastname


update dbo.mytable$
set       firstname = Replace(Firstname,reverse(left(reverse(firstname),len(firstname)-1)),  reverse(lower(left(reverse(firstname),len(firstname)-1)))),
lastname = Replace(Lastname,reverse(left(reverse(Lastname),len(Lastname)-1)),  reverse(lower(left(reverse(Lastname),len(Lastname)-1))))
where LastName = 'PIZER'


result I am getting on lastname is =  PIzer
I am expecting lastname to be Pizer

 where have i gone wrong.
0
Amanda Walshaw
Asked:
Amanda Walshaw
3 Solutions
 
Koen Van WielinkBusiness Intelligence SpecialistCommented:
Hi Flyfish,

When I run the exact script I get the expected result. Try this test script below:

Create table #temp
(lastname nvarchar(100))

insert into #temp
values ('PIZER')

Select lastname = Replace(Lastname,reverse(left(reverse(Lastname),len(Lastname)-1)),  reverse(lower(left(reverse(Lastname),len(Lastname)-1))))
from #temp

drop table #temp

Open in new window


Rgds,

Kvwielink
0
 
Raja Jegan RSQL Server DBA & ArchitectCommented:
Try this which should work..

update dbo.mytable$
set firstname = UPPER(substring(firstname, 1, 1)) + LOWER(substring(firstname, 2, LEN(firstname)))
    ,lastname = UPPER(substring(lastname, 1, 1)) + LOWER(substring(lastname, 2, LEN(lastname)))
where LastName = 'PIZER'
0
 
PaulCommented:
declare @lastname varchar(80) = 'PIZER'

select
  lastname = substring(@lastname,1,1) + lower(substring(@lastname,2,80))
0
 
Koen Van WielinkBusiness Intelligence SpecialistCommented:
Hi Flyfish,

Just wondering if you might have some spaces at the end of the name.
Try to put the lastname column between trim statements:

LTRIM(RTRIM(lastname))

By the way, I'm feeling really stupid seeing how complicated my method was to change the uppercase to lowercase....
0
 
mimran18Commented:
Please use Datalength function instead of LEN function
0
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