Dir for loop get path details.

I have the following code...

FOR /f "delims=" %%f in ('dir /b /a-d-h c:\source\*.*') DO (
 Echo %%f >> Output
)

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I know nothing about DOS but am looking to expand this in some way so that I can get both the file path and its name in separate variables? I also need a way of determining whether I am iterating on the first file in the loop - if so I want to use > to echo to a fresh file - otherwise I want to use >> to append to the file? Any ideas?
Blowfelt82Asked:
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Steve KnightIT ConsultancyCommented:
Sorry, I missed the fact you weren't doing sub directories.  If you had /s then it would include the path in the dir output and work.

If you want subdirs too add /s and it will work (or if there are no subdirs) or do away with the dir command:

@echo off
(FOR %%F in (c:\source\*.*) DO (
 Echo "%%~dpF","%%~nxF","%%~zF","%%~tF"
))> Output.csv

Steve
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oBdACommented:
You can access the path of a "for" variable X using "%~dpX" (see "help call" for details), the name and extension with %~nxX; and if you want to set and expand variables inside a "for" loop, you need delayed variable expansion (see "help set" for details):
@echo off
setlocal enabledelayedexpansion
set OutputFile=Output.txt
if exist "%OutputFile%" del "%OutputFile%"
FOR /f "delims=" %%f in ('dir /b /a-d-h c:\source\*.*') DO (
  set FilePath=%~dpf
  set FileName=%~nxf
  echo File path: !FilePath!
  echo File name: !FileName!
  echo %%f >>"%OutputFile%"
)

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djbaumCommented:
If you just want the overview, you can use this:
tree /f

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Steve KnightIT ConsultancyCommented:
Ok, try this.  Putting ( ) around commands will do it all in one go so one file operation creating file.  You can get different bits of file name and size etc. using operators on %%f, have shown some here to get path, name, size but see for /? for more.  I have changed %%f to %%F just to make it clearer in the other bits.  The ~ removes the "" characters around any files with spaces in so can re-add them to all for CSV type output.


@echo off
(FOR /f "delims=" %%F in ('dir /b /a-d-h c:\source\*.*') DO (
 Echo "%%~dpF","%%~nxF","%%~zF","%%~tF"
))> Output.csv
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Steve KnightIT ConsultancyCommented:
11 seconds slow there in posting :-)
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Blowfelt82Author Commented:
Thanks for the posts so far, DragonIT your solution looks good but when I run it the %%~dpF command returns the path of the executing batch file and not of the file. This is I think an issue with my original DIR command which looking at it more closely does not include the path of the file in the output?
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Blowfelt82Author Commented:
Perfect! Thanks for the help!
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Steve KnightIT ConsultancyCommented:
No problem, don't forget to "accept" the answer(s)
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Blowfelt82Author Commented:
Sorry for the late 'Accept'!
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