zimmer9
asked on
How would you convert the following .SRT file's contents into plain text via DOS command?
How would you convert the following .SRT file's contents into plain text stripping out the
line number and time information lines using DOS?
I have attached a .SRT file with the following contents:
I was hoping to convert the following .SRT file's contents from
6
00:00:27,000 --> 00:00:30,000
and build some simple webpages.
7
00:00:30,000 --> 00:00:33,000
Part of what makes web design and web development so fun
8
00:00:33,000 --> 00:00:37,000
when compared to other forms of software development, is that you can
to revised values as follows:
and build some simple webpages.
Part of what makes web design and web development so fun
when compared to other forms of software development, is that you can
TEST.txt
line number and time information lines using DOS?
I have attached a .SRT file with the following contents:
I was hoping to convert the following .SRT file's contents from
6
00:00:27,000 --> 00:00:30,000
and build some simple webpages.
7
00:00:30,000 --> 00:00:33,000
Part of what makes web design and web development so fun
8
00:00:33,000 --> 00:00:37,000
when compared to other forms of software development, is that you can
to revised values as follows:
and build some simple webpages.
Part of what makes web design and web development so fun
when compared to other forms of software development, is that you can
TEST.txt
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ASKER
The numbers still appear in the output. For ex:
6
and build some simple webpages.
7
Part of what makes web design and web development so fun
8
when compared to other forms of software development, is that you can
6
and build some simple webpages.
7
Part of what makes web design and web development so fun
8
when compared to other forms of software development, is that you can
Redirection to another output is shown above (> TEST_stripped.txt).
My output is this:
test_stripped.txt has the output you requested, without the numbered lines and without the empty lines.
Did you copy/paste the findstr pattern correctly? There are (important) spaces in there, these are required.
My output is this:
C:\Temp>type test.txt
6
00:00:27,000 --> 00:00:30,000
and build some simple webpages.
7
00:00:30,000 --> 00:00:33,000
Part of what makes web design and web development so fun
8
00:00:33,000 --> 00:00:37,000
when compared to other forms of software development, is that you can
C:\Temp>findstr /v /r "^$ --> ^[0-9]*$" test.txt > test_stripped.txt
C:\Temp>type test_stripped.txt
and build some simple webpages.
Part of what makes web design and web development so fun
when compared to other forms of software development, is that you can
C:\Temp>
test_stripped.txt has the output you requested, without the numbered lines and without the empty lines.
Did you copy/paste the findstr pattern correctly? There are (important) spaces in there, these are required.
ASKER