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Drop down box in order

Posted on 2013-05-31
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Last Modified: 2013-06-18
Ive got some simple code to populate a select box with the hours of the day:-
        $.each({"00":"00", "01":"01", "02":"02", "03":"03", "04":"04", "05":"05", "06":"06", "07":"07", "08":"08", "09":"09", "10":"10", "11":"11", "12":"12", "13":"13", "14":"14", "15":"15", "16":"16", "17":"17", "18":"18", "19":"19", "20":"20", "21":"21", "22":"22", "23":"23" }, function(key, value) {
            $('.ddHH')
                .append($('<option>', { value : key })
                .text(value));
            });

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Which works great however the drop down populates like:-
10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 00, 01, 02, 03, 04, 05, 06, 07, 08, 09

But I want it to populate as:-
00, 01, 02, 03, 04, 05, 06, 07, 08, 0910, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23

I dont understand where the 'sorting' is coming in, as surely it would just take the first element of the array add it, then the second. I would understand if it was reveresed, but dont understand this :-(

Any ideas?

Thank you
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Question by:tonelm54
3 Comments
 
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by:leakim971
leakim971 earned 1000 total points
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Accepted Solution

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Gary earned 1000 total points
ID: 39211078
Your code works fine for me.
http://jsfiddle.net/Sqqbg/1/
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Author Closing Comment

by:tonelm54
ID: 39257095
Hmm, dont understand then, must be me :-S

Thanks for your help
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