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  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 433
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How do I sum a count on nvarchar.

Current:
Select  Company_Id ci, count (distinct Order_Number) cnt
From TableA
Having  Count(Order_Number) >1

Order Number is a alpha numeric, example PQR0725102115, and is nvarchar.

Yields:

Ci            cnt
1               10
2                 2
3                 6
4               15

Desired result:

I need the sum of the cnt column:

cnt
33

The problem is in the nvarchar.
0
rhservan
Asked:
rhservan
  • 2
1 Solution
 
dsackerContract ERP Admin/ConsultantCommented:
Don't think the problem really is the nvarchar. You're definitely on the right track, but simply may need to sum what you just queried.

Try this:

Select  ci,
        SUM(cnt) AS cntSum
From  ( Select  Company_Id AS ci,
                count (distinct Order_Number) AS cnt
        From    TableA
        Having  Count(Order_Number) >1 ) t1
Group By ci

Open in new window

I added the "AS" simply for readability.
0
 
rhservanAuthor Commented:
Hey dsacker thanks for the help.

After implementing your solution I still get

Ci            cnt
1               10
2                 2
3                 6
4               15

I need just one row sum result on cnt:

cnt
33
0
 
dsackerContract ERP Admin/ConsultantCommented:
This should work. :)

Select  SUM(cnt) AS cntSum
From  ( Select  Company_Id AS ci,
                count (distinct Order_Number) AS cnt
        From    TableA
        Having  Count(Order_Number) >1 ) t1

Open in new window

0

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