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How to find value in text

Posted on 2013-06-03
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Last Modified: 2013-06-04
I am not sure which function to use to find the text I am looking for.  I thought it was the CHARINDEX but it is not returning the desired results.  I am looking for the name which starts in the same location every time but can be different lengths.  The end of the name is designated by a space.  I am using the following logic:

SUBSTRING(MASTER24_HISTORY.MRHISTORY,21,CHARINDEX(' ', LEFT(MASTER24_HISTORY.mrHISTORY,22)))

However it is pulling more than just the name.  Any idea why?
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Question by:Gary Harper
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3 Comments
 
LVL 46

Accepted Solution

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Kent Olsen earned 1200 total points
ID: 39217553
Hi GHarper,

It looks like you're mixing techniques.  :)

First limit the variable (chop off the bit to the right:
  LEFT (item, charindex (item, ' ', start))

Then grab the desired portion:
  SUBSTRING (LEFT (item, charindex (item, ' ', start), start, limit)

Limit is the size of the variable.  You can compute a value, but this is easier to code.


Good Luck,
Kent
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LVL 40

Expert Comment

by:lcohan
ID: 39219448
I suggest you look for PATINDEX ( '%pattern%' , expression ) to find the possition of the ' ' - or space char in your string and build/calculate your SUBSTRING based on that.
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Author Comment

by:Gary Harper
ID: 39219538
kdo pointed me in the right direction.  I ended up using

SUBSTRING(item,21,CHARINDEX(' ',item,21) - 21) as 'Username'
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