sql for duplicate rows in table

yes, do the below

;with cte
(
 select row_number() over(parition by <all your columns> order by (select 1)) rn,* from <your table>
)
select * from cte where rn>1

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in the above code, replace the
<all your columns> with the columns list of your table
<your table> with your table name.

<<SELECT Column1, Column2, Column3, Column4, Count(Column4) as duplicate_rows
FROM YourTable
GROUP BY Column1, Column2, Column3, Column4
HAVING COUNT(Column4) > 1
ORDER BY COUNT(Column4) DESC >>

looks good, i am trying to get a total sum of the duplicate rows
but this doesnt seem to work

SELECT Column1, Column2, Column3, Column4, Count(Column4) as duplicate_rows,
SUM(duplicate_rows)
FROM YourTable
GROUP BY Column1, Column2, Column3, Column4
HAVING COUNT(Column4) > 1
ORDER BY COUNT(Column4) DESC

thanks

try this.

SELECT Column1,Column2,Column3,Column4,duplicate_rows,
      SUM(duplicate_rows) OVER ( partition BY (SELECT 1)) sum_duplicate_rows
  FROM (SELECT Column1,Column2,Column3,Column4,COUNT(Column4) AS duplicate_rows 
          FROM YourTable 
         GROUP BY Column1,Column2,Column3,Column4 
        HAVING COUNT(Column4) > 1) t1 
 ORDER BY duplicate_rows DESC 

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<somewhat redundant with the above comments>

>i am trying to get a total sum of the duplicate rows
Throw the whole thing in a subquery, and sum.  
Replace the SUM with COUNT if you want distinct duplicate row columns.

SELECT SUM(a.duplicate_rows)
FROM (
   SELECT Column1, Column2, Column3, Column4, Count(Column4) as duplicate_rows,
   SUM(duplicate_rows)
   FROM YourTable
   GROUP BY Column1, Column2, Column3, Column4
   HAVING COUNT(Column4) > 1
   ORDER BY COUNT(Column4) DESC ) a

Any help with this question will be greatly appreciated
https://www.experts-exchange.com/questions/28148609/checksum-autogeneration.html

Thanks for the grade.  Good luck with your project.  -Jim