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How to make a 2nd. combo to use the option choosed at the 1st combo?

Posted on 2013-06-04
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Last Modified: 2013-06-05
Hi Experts!

How to make a 2nd. combo to use the option choosed at the 1st combo?

Accordingly to the code bellow, the way it's coded the 2nd. combo doesn't use the 1st. combo parameter.


<?php

....

    //----------Code start Combo (DSGER Despesa Hierárquica)--------------------------------------------
  $nivel=1;    // default parameter

 $sql1 = "select sb_dge, dge_info, substr(descricao,1,25) as descricao from dsger 
             where tipo=2 and nivel=".$nivel." order by descricao;";

    // Configurar o nivel:
     $query1 = mysql_query($sql1);
     while ( $results1[] = mysql_fetch_object ( $query1 ) );
     array_pop ( $results1 );
    //----------Final Combo 2-------------------------------------------------------------------------

....

<br/>
/////// 1st. Combo that furnish the parameter "nível" //////
Nivel Totalizador Despesa:
<select name="nivel">
    <option value="1">    1     </option>
    <option value="2">    2     </option>
</select>

<?php
   //After choosen 1st. parameter

    //----------Inicio Combo 2 (DSGER Despesa Hierárquica)--------------------------------------------

     echo "Nivel....".$nivel;

     $sql1 = "select sb_dge, dge_info, substr(descricao,1,25) as descricao from dsger 
             where tipo=2 and nivel=".$nivel." order by descricao;";

    // Configurar o nivel:
     $query1 = mysql_query($sql1);
     while ( $results1[] = mysql_fetch_object ( $query1 ) );
     array_pop ( $results1 );
    //----------Final Combo 2-------------------------------------------------------------------------
?>

<br/>
Despesa (H):
<select name="sb_dsg">
<?php 
     //----------Intend to present Combo 2 configured--------------------
     foreach ( $results1 as $option ) : ?>
          <option value="<?php echo $option->sb_dsg; ?>"><?php echo $option->descricao; ?></option>
<?php 
     endforeach; 
?>
</select> 

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What must be done ?

Thanks in advance!
0
Comment
Question by:Eduardo Fuerte
  • 2
  • 2
5 Comments
 
LVL 109

Accepted Solution

by:
Ray Paseur earned 250 total points
ID: 39220813
Sometimes it is all about how you ask the question.  In this case, it is!

Please make a Google search for jquery dependent dropdown.
0
 
LVL 15

Assisted Solution

by:Jagadishwor Dulal
Jagadishwor Dulal earned 250 total points
ID: 39220901
0
 

Author Comment

by:Eduardo Fuerte
ID: 39221699
Ok, I'm seeking...
0
 

Author Closing Comment

by:Eduardo Fuerte
ID: 39222305
Thanks for your assistance, again....
I was miles away from solution before it...
I'm new in PHP and getting more proficiency with your replies!
0
 
LVL 109

Expert Comment

by:Ray Paseur
ID: 39222335
jQuery (client side JavaScript) intersects PHP (server side script) in the AJAX technology.  You might find this article interesting.
http://www.experts-exchange.com/Programming/Languages/Scripting/JavaScript/Jquery/A_10712-The-Hello-World-Exercise-with-jQuery-and-PHP.html

Thanks for the points, ~Ray
0

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