Eduardo Fuerte
asked on
How to make a 2nd. combo to use the option choosed at the 1st combo?
Hi Experts!
How to make a 2nd. combo to use the option choosed at the 1st combo?
Accordingly to the code bellow, the way it's coded the 2nd. combo doesn't use the 1st. combo parameter.
What must be done ?
Thanks in advance!
How to make a 2nd. combo to use the option choosed at the 1st combo?
Accordingly to the code bellow, the way it's coded the 2nd. combo doesn't use the 1st. combo parameter.
<?php
....
//----------Code start Combo (DSGER Despesa Hierárquica)--------------------------------------------
$nivel=1; // default parameter
$sql1 = "select sb_dge, dge_info, substr(descricao,1,25) as descricao from dsger
where tipo=2 and nivel=".$nivel." order by descricao;";
// Configurar o nivel:
$query1 = mysql_query($sql1);
while ( $results1[] = mysql_fetch_object ( $query1 ) );
array_pop ( $results1 );
//----------Final Combo 2-------------------------------------------------------------------------
....
<br/>
/////// 1st. Combo that furnish the parameter "nível" //////
Nivel Totalizador Despesa:
<select name="nivel">
<option value="1"> 1 </option>
<option value="2"> 2 </option>
</select>
<?php
//After choosen 1st. parameter
//----------Inicio Combo 2 (DSGER Despesa Hierárquica)--------------------------------------------
echo "Nivel....".$nivel;
$sql1 = "select sb_dge, dge_info, substr(descricao,1,25) as descricao from dsger
where tipo=2 and nivel=".$nivel." order by descricao;";
// Configurar o nivel:
$query1 = mysql_query($sql1);
while ( $results1[] = mysql_fetch_object ( $query1 ) );
array_pop ( $results1 );
//----------Final Combo 2-------------------------------------------------------------------------
?>
<br/>
Despesa (H):
<select name="sb_dsg">
<?php
//----------Intend to present Combo 2 configured--------------------
foreach ( $results1 as $option ) : ?>
<option value="<?php echo $option->sb_dsg; ?>"><?php echo $option->descricao; ?></option>
<?php
endforeach;
?>
</select>
What must be done ?
Thanks in advance!
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SOLUTION
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ASKER
Thanks for your assistance, again....
I was miles away from solution before it...
I'm new in PHP and getting more proficiency with your replies!
I was miles away from solution before it...
I'm new in PHP and getting more proficiency with your replies!
jQuery (client side JavaScript) intersects PHP (server side script) in the AJAX technology. You might find this article interesting.
https://www.experts-exchange.com/Programming/Languages/Scripting/JavaScript/Jquery/A_10712-The-Hello-World-Exercise-with-jQuery-and-PHP.html
Thanks for the points, ~Ray
https://www.experts-exchange.com/Programming/Languages/Scripting/JavaScript/Jquery/A_10712-The-Hello-World-Exercise-with-jQuery-and-PHP.html
Thanks for the points, ~Ray
ASKER