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bash MySQL result into array

Posted on 2013-06-07
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Last Modified: 2013-07-23
I have a script that runs every 15 minutes which looks for phone calls in a database and groups them by the sourceTN counting calls.  The query and result is below.  My questions is I need to be able to store each row (sourceTN and Calls) into a temporary variable so I can crank it through and IF statement to see if a telephone number has a value greater then 10.  Something like...

IF Calls > 10
THEN
  # do some actions with the SourceTN


Query:
SELECT src as SourceTN, COUNT(src) as Calls FROM cdr GROUP BY src;"

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+------------+-------+
| SourceTN   | Calls |
+------------+-------+
| 2012680000 |    27 | 
| 2016240000 |     1 | 
| 2018160000 |     2 | 
| 2018160000 |     5 | 
| 2018160000 |     7 | 
| 2018160000 |     9 | 
| 2018160000 |     1 | 
| 2018160000 |     4 | 
 

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Question by:ipconfig610
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2 Comments
 
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Accepted Solution

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Manuel Marienne-Duchêne earned 2000 total points
ID: 39228766
SELECT SOURCETN,CASE WHEN CALLS > 10 THEN ....ELSE .... END FROM (SELECT src as SourceTN, COUNT(src) as Calls FROM cdr GROUP BY src) TABLE1
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LVL 38

Expert Comment

by:Gerwin Jansen, EE MVE
ID: 39232698
Where is the output of your query going? To some temporary file perhaps?

In case the output goes to a temporary file, you could parse the file and search for lines matching your 'clause' > 10 calls using awk for example.

If possible can you post (part of your) script?
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