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Why virtual desctructor?

Posted on 2013-06-11
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Last Modified: 2013-06-11
class Socket   // This is an Interface class and must be overriden to work.
{
  public:  
    enum SocketErrorValue
    {
      SocketErrorValue_None             = 0,
      SocketErrorValue_SocketNotOpen    = -1,
      SocketErrorValue_ConnectionClosed = -2,
      SocketErrorValue_WriteBufferFull  = -3,
      SocketErrorValue_InvalidParameter = -4,
      SocketErrorValue_Timeout          = -5,
      SocketErrorValue_NoData           = -6,
      SocketErrorValue_InListenMode     = -7
    };


    /// <summary>Descructor
    /// </summary>
    virtual ~Socket() {};
    ...
    ...


In above base class, is destrctor 'virtual' so it can be overridden by a class that inherits this base class?
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Question by:naseeam
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jkr earned 400 total points
ID: 39238365
The reason for the destructor being virtual is to ensure that the base class' destructors are calledm and that will happen in the right order. See http://www.codersource.net/c/c-miscellaneous/c-virtual-destructors.aspx ("C++ Virtual destructors") and http://blogs.msdn.com/b/oldnewthing/archive/2004/05/07/127826.aspx ("When should your destructor be virtual?")
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by:naseeam
ID: 39238501
Great articles that anwer the exact question asked.
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