Convert varchar into int

Trying to convert data in varchar format into an integer so I can sum the values.
However, some of the data contains strings like '-11.73' or '$1.23' or '$1,500'
I am getting the error below with this code. Please help. Thanks.

Msg 245, Level 16, State 1, Line 3
Conversion failed when converting the varchar value '-11,73' to data type int.


SELECT
'YTD' as "Totals"
,'System' as "Type"
,count(distinct c.ch_trade_error_id) as "Total Trade Errors"
,sum(case when cast(replace(c.amount,'.',',') as int) *-1 < 0 then cast(replace(c.amount,'.',',') as int) else 0 end) as Gain


FROM
CHAMP.V_TRADE_ERRORS c


WHERE
c.ORIGINATION_DATE between '2013-01-01' and '2013-05-31'
and c.REP_NAME is null
saved4useAsked:
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Racim BOUDJAKDJIConnect With a Mentor Database Architect - Dba - Data ScientistCommented:
replace

sum(case when cast(replace(c.amount,'.',',') as int) *-1 < 0 then cast(replace(c.amount,'.',',') as int) else 0 end)

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by

sum(case when cast(replace(floor(c.amount),'.',',') as int) *-1 < 0 then cast(replace(floor(c.amount),'.',',') as int) else 0 end)

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saved4useAuthor Commented:
Used the above and got the error below:

Msg 8114, Level 16, State 5, Line 3
Error converting data type varchar to float.
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Racim BOUDJAKDJIDatabase Architect - Dba - Data ScientistCommented:
You perhaps have some value stored in varchar that are non numeric value.  You need to get rid of these first by identifying them.

Run below to do that...

select top 1000 c.amount
from CHAMP.V_TRADE_ERRORS
where isnumeric(c.amount) <> 1

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saved4useAuthor Commented:
@Racimo You are right! How do I get rid of them? *I definitely need to sum those amounts in parenthesis and dollar sign. Here they are

amount
--------------------
$487-50
(.12)
(.72)
(.84)
(0.03)
(0.27)
(0.73)
(1)
(1.30)
(10.00)
(10.09)
(102.00)
(1035.31)
(104.91)
(11.58)
(12.00)
(120.65)
(1204.10)
(130)
(1400.00)
(15.00)
(150.00)
(156)
(16.00)
(178.52)
(1947.17)
(198)
(2.00)
(2.08)
(20.00)
(200)
(21.35)
(212.84)
(214)
(219)
(220)
(226.73)
(230)
(24.00)
(250)
(26.00)
(260.84)
(278.17)
(28.50)
(28.70)
(3.24)
(32.57)
(324.97)
(33.00)
(33.44)
(330.00)
(35)
(3557.71)
(37.92)
(375.18)
(398.26)
(43.50)
(436.65)
(44.00)
(45.00)
(450)
(5.12)
(5.60)
(5.69)
(532.66)
(54.00)
(54.07)
(57.60)
(6.00)
(679.90)
(7.15)
(70.40)
(734.85)
(750)
(80.00)
(81.71)
(813.00)
(84.76)
(99.19)
*
**
***
****
*****
******
*******
*****************
N/A
NOT KNOWN

(89 row(s) affected)
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Racim BOUDJAKDJIDatabase Architect - Dba - Data ScientistCommented:
How do I get rid of them?
1> Well for one, it seems some values are stored in parenthesis.  You simply need to get rid of these parenthesis by running something like

update CHAMP.V_TRADE_ERRORS
set c.amount = substring(rtrim(c.amount), 2, len(rtrim(c.amount)) -2)
where isnumeric(c.amount) <> 1 and left(rtrim(c.amount), 1) = '('
and right(rtrim(c.amount), 1) = ')'

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once you get this simply delete values that can not be used at all by running

delete
from CHAMP.V_TRADE_ERRORS
where isnumeric(c.amount) <> 1

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Racim BOUDJAKDJIDatabase Architect - Dba - Data ScientistCommented:
Yes and please test this before running into production.
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PortletPaulfreelancerCommented:
use of parentheses can be used to indicate negative

just as an observation here, do values within parentheses indicate a NEGATIVE number?
if so, removing the parentheses without also negating the value would produce an incorrect total.

also, for the first listed value above: $487-50

is this $437 ($487 - $50) or $487.50?

{+edit}
my guess is that this data is coming from Excel
N/A indicates some sort of logical error
and ***** may indicate another form of logical error

{+edit 2}
and why are you converting decimals to integer anyway?
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PortletPaulfreelancerCommented:
&&
TRUE_AMOUNT_SUM  SUM_AMOUNT_TO_INT  INT_AMOUNT_SUM
-19572.69                     -19573                               -19576

taking those numbers in parentheses, pasting into Excel (automatically treated as negatives), then using in sql server and then summing with this:
select
  sum(amount) as true_amount_sum
, cast(sum(amount) as int) as sum_amount_to_int
, sum(cast(amount as int)) as int_amount_sum
from table1
http://sqlfiddle.com/#!3/78de3/3
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