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Remove duplicates from Left Outer Join

Posted on 2013-06-12
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Last Modified: 2013-06-12
Hi -
How do I remove duplicate Usernames from the query below.   I changed the query from a cross join to a left outer join to eliminate massive amounts of records.   Now I have the issue of retreiving multiple usernames (I'm grouping by MEMBEROF in the crystal report)

WITH EmployeeList AS
(SELECT DISTINCT   A.DistinguishedName,
                      A.AccountName,
                      A.DisplayName,
                      A.Type,
                      B.MEMBEROF,
                      B.USERNAME
FROM         ADUsersAndGroups A                
LEFT OUTER JOIN GROUPS B ON A.DistinguishedName = B.MEMBEROF
                 
UNION

SELECT DISTINCT  A.DistinguishedName,
                      A.AccountName,
                      A.DisplayName,
                      A.Type,
                      B.MEMBEROF,
                     B.USERNAME
FROM         ADUsersAndGroups A
LEFT OUTER JOIN GROUPS B ON A.AccountName = B.USERNAME)
SELECT * FROM EmployeeList
WHERE DisplayName is not NULL;


I'm trying to acheive the following output in the report:
Where user's are grouped by groupname.
MEMBEROF  (GROUPNAME)
          USERNAME (USERID)        DISPLAYNAME (User name)


However, I'm currently getting output were Display name is blank or populated with group information and the Username is diplaying multiple times.

Any help would be greatly appreciated.    Thanks!!  Mojeaux
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Question by:mojeaux
5 Comments
 
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Accepted Solution

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mlmcc earned 2000 total points
ID: 39242734
I think you want to limit the first query to type = GROUP and the second to type = user

Can a group have a group?

mlmcc
0
 
LVL 4

Expert Comment

by:BAKADY
ID: 39242738
please post some example of the data/records you get duplicated...
0
 
LVL 5

Expert Comment

by:DOSLover
ID: 39242758
I think instead of 'UNION', you can use OR condition in left outer join:
SELECT DISTINCT   A.DistinguishedName, 
                      A.AccountName, 
                      A.DisplayName, 
                      A.Type,
                      B.MEMBEROF, 
                      B.USERNAME
FROM ADUsersAndGroups A                 
LEFT OUTER JOIN GROUPS B ON (A.DistinguishedName = B.MEMBEROF OR A.AccountName = B.USERNAME)

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LVL 101

Expert Comment

by:mlmcc
ID: 39243324
The union is required since that makes it recursive.

mlmcc
0
 

Author Closing Comment

by:mojeaux
ID: 39243347
Thank you!  I was able to reach the same conclusion....thank goodness for you guys on EE!  Y'all are my 'goto' guys!
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