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Which constructor is being called?

Posted on 2013-06-14
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Last Modified: 2013-06-14
Two constructors are as follows:

UsbSocket::UsbSocket(unsigned short tId)
: _callTask(tId),
  ...
{
  ...
  ...
}


UsbSocket::UsbSocket(unsigned short rxBuffsize, unsigned short txBuffsize, unsigned short tId)
: _callTask(tId),
  ...
{
 ...
 ....
}


A class is getting instantiated as follows:

UsbSocket *_usb;

_usb = new UsbSocket();


I believe above Two constructors are not getting called.  Is the default constructor getting called?

We work on embedded ARM7 based target.  We used Keil Tools.
If the default constructor is getting called, what does it do?  Do I need to look at the compiler manual to find out what the default constructor does in my system?
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Question by:naseeam
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4 Comments
 
LVL 86

Assisted Solution

by:jkr
jkr earned 2000 total points
ID: 39248312
>>I believe above Two constructors are not getting called.  Is the default constructor getting
>>called?

Yes, indeed - only the default constructor matches the argument list (i.e. no arguments at all). Only if the 1st ctor would have a default argulent like 'UsbSocket::UsbSocket(unsigned short tId = 0)', it would match. Since that is not the case, the default constructor is used.
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Author Comment

by:naseeam
ID: 39248325
What does the default constructor do?  There are so many members in this class.  I need to know what are they getting initialized to.
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LVL 86

Accepted Solution

by:
jkr earned 2000 total points
ID: 39248364
If there is no default constructor in the code, a compiler-generated one will be invoked. This one only does a minimum amount of initialization (will depend on the compiler). The best would be if you would provide your own default constructor,
0
 
LVL 1

Author Closing Comment

by:naseeam
ID: 39248679
Thanks for explaining  the constructor confusion.
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