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how to organize sequence of words by size

hi, lets say i have this var inside one storeprocedure and i want to accomplish this

DECLARE @STR VARCHAR(300) = 'I Love to eat steak in the restaurant'

what i want is to organize the words by size with , between them and not include words that have less then 3 characters.

restaurant, steak, Love, the
0
rafaelrgl
Asked:
rafaelrgl
1 Solution
 
Surendra NathCommented:
the solution below needs you to create a user defined function first...
The user defined function is split by a charecter and return a table.

The below is the code for that user defined function split... you can know more about it at the link http://everysolution.wordpress.com/2011/07/28/udf-to-split-a-delimited-string-and-return-it-as-a-table/

CREATE FUNCTION dbo.Split
(
 @RowData nvarchar(2000),
 @SplitOn nvarchar(5)
)
RETURNS @RtnValue table
(
 Id int identity(1,1),
 Data nvarchar(100)
)
AS
BEGIN
 Declare @Cnt int
 Set @Cnt = 1
 DECLARE @index INT
 SET @index = Charindex(@SplitOn,@RowData)
 While (@index>0)
 Begin
 Insert Into @RtnValue (data)
  Select
 Data = ltrim(rtrim(Substring(@RowData,1,@index-1)))
 
 Set @RowData = Substring(@RowData,@index+1,len(@RowData))
 Set @Cnt = @Cnt + 1
 SET @index = Charindex(@SplitOn,@RowData)
 End
 
 Insert Into @RtnValue (data)
 Select Data = ltrim(rtrim(@RowData))
 
 Return
END

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after creating this function then you can write your code as below

DECLARE @STR VARCHAR(300) = 'I Love to eat steak in the restaurant'
;with CTE AS
(
 select Data,len(Data) as L FRom dbo.split(@STR,' ')
)
select stuff((select ','+Data From CTE where L > 2 for xml path('')),1,1,'')

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0
 
rafaelrglAuthor Commented:
Thanks man, your function help me understand and build the right solution, but the points still goes to you, here is what i want:

DECLARE @KEYWORDS VARCHAR(8000) = 'I Love to eat steak in the restaurant'
DECLARE @TB1 TABLE(VWORD NVARCHAR(100))
DECLARE @CNT INT = 1
DECLARE @INDEX INT = CHARINDEX(' ',@KEYWORDS)
While (@index>0)
Begin
     Insert Into @TB1
     Select ltrim(rtrim(Substring(@KEYWORDS,1,@index-1)))
 
     Set @KEYWORDS = Substring(@KEYWORDS,@index+1,len(@KEYWORDS))
     Set @Cnt = @Cnt + 1
     SET @index = Charindex(' ',@KEYWORDS)
End
Insert Into @TB1
Select ltrim(rtrim(@KEYWORDS))
DECLARE @RESULT VARCHAR(2000)
SELECT @RESULT = COALESCE(@RESULT + ', ', '') + VWORD FROM @TB1 WHERE LEN(VWORD) > 3 ORDER BY LEN(VWORD) DESC
SELECT @RESULT
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