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How to check if a 7 character string contains one letter and six numbers?

Experts,

I need to adjust the following script to check to see if the variable being passed contains:

- 1 regular character (letter a-z, capitalization is not important)

and

- 6 numbers

I've tried several variations of what I though should work but, am just getting frustrated at this point.

Cheers!

var x=document.forms["step1"]["alt_user"].value;
if((x.length =="7" && CHECK FOR LETTER AND ^ NUMBERS HERE) || (x == null || x == "")){}

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evibesmusic
Asked:
evibesmusic
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1 Solution
 
GaryCommented:
How about a regex - this pattern
(?:^[a-zA-Z]{1}[0-9]{6})

Checks if first character a letter and then 6 numbers - wasn't clear from your question the makeup of the string.
If it doesn't matter the order just remove the ^

http://jsfiddle.net/wNDCh/1/
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evibesmusicAuthor Commented:
@GaryC123

Your assumption was spot on. Sorry for not making that more clear.

The string being passes should be in the following format:

x123456

To implement your suggestion would my code then look like this?

var x=document.forms["step1"]["alt_user"].value;
if((x.length =="7" && x==(?:^[a-zA-Z]{1}[0-9]{6})) || (x == null || x == "")){}

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GaryCommented:
check the jsfiddle link
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GaryCommented:
var x=document.forms["step1"]["alt_user"].value;
var regPattern=/(^[a-zA-Z]{1}[0-9]{6})/

if (x.search(regPattern)==-1){ //no match
    // code for no match
}
else{ // matched
    // code here for match
}

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This doesn't take account for accented characters etc...
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evibesmusicAuthor Commented:
Perfect. Thank you very much!
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