SQL - Query Location table where ADDR1 have duplicated values

Hello all

I'm trying to extract from my LOCATION table all locations that have duplicated values in column ADDR1 field but using the SQL below.

But i have this error: ORA-00933: SQL command not properly ended

How can i fix this?

Thanks again for your help.


SELECT CNT, 
    'L' AS L,
         'M' AS M,
         ID,
         DECODE (LOC_TYPE_ID,
                 0,
                 'PLAN',
                 1,
                 'CUSTOMER',
                 2,
                 'VENDOR',
                 3,
                 'DIST',
                 5,
                 'CROSSDOCK')
            AS LOC_TYPE_ID,
         NAME,
         ADDR1,
         ADDR2,
         CITY,
         STATE,
         COUNTRY,
         ZIP,
         CONTACT,
         PHONE,
         PHONE_SPD,
         FAX,
         LATITUDE,
         LONGITUDE,
         ZONE,
         PU_STOPTM,
         DEL_STOPTM,
         APPOINTMENT_REQUIRED,
         TIME_ZONE_ID,
         LOAD_CLASS_ID,
         CONSOLIDATION_ALLOWED,
         PARCEL_SERVICE,
         LOCATION_GROUP,
         MAX_CROSSDOCK_DAYS,
         PARCEL_CARRIER,
         ALT_LOCATION_ID,
         LOC_ROUTING_CLASS_ID,
         PICK_SRV_CLASS_ID,
         DELV_SRV_CLASS_ID,
         SPLC,
         APPOINTMENT_HONORED,
         SPLIT_WEIGHT,
         SPLIT_CUBE,
         SPLIT_PALLET,
         SPLIT_PIECES,
         SET_ID,
         SHIP_PRIORITY_ID,
         EMAIL,
         TRADE_AREA,
         SCNALIAS,
         XDOCK_HANDLING_TIME,
         SHPPTY,
         XDOCK_LIVE_LOADING,
         OWNER,
         PORT_CODE,
         NOTES
  FROM   LOCATION
(
SELECT COUNT(*) CNT,
    ADDR1
FROM 
      LOCATION
-GROUP BY ADDR1
HAVING COUNT > 1; 

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LVL 11
Wilder1626Asked:
Who is Participating?
 
slightwv (䄆 Netminder)Connect With a Mentor Commented:
The syntax error is due to a missing ')'

Try this one:
select * from 
(
SELECT CNT, 
    'L' AS L,
         'M' AS M,
         ID,
         DECODE (LOC_TYPE_ID,
                 0,
                 'PLAN',
                 1,
                 'CUSTOMER',
                 2,
                 'VENDOR',
                 3,
                 'DIST',
                 5,
                 'CROSSDOCK')
            AS LOC_TYPE_ID,
         NAME,
         ADDR1,
         ADDR2,
         CITY,
         STATE,
         COUNTRY,
         ZIP,
         CONTACT,
         PHONE,
         PHONE_SPD,
         FAX,
         LATITUDE,
         LONGITUDE,
         ZONE,
         PU_STOPTM,
         DEL_STOPTM,
         APPOINTMENT_REQUIRED,
         TIME_ZONE_ID,
         LOAD_CLASS_ID,
         CONSOLIDATION_ALLOWED,
         PARCEL_SERVICE,
         LOCATION_GROUP,
         MAX_CROSSDOCK_DAYS,
         PARCEL_CARRIER,
         ALT_LOCATION_ID,
         LOC_ROUTING_CLASS_ID,
         PICK_SRV_CLASS_ID,
         DELV_SRV_CLASS_ID,
         SPLC,
         APPOINTMENT_HONORED,
         SPLIT_WEIGHT,
         SPLIT_CUBE,
         SPLIT_PALLET,
         SPLIT_PIECES,
         SET_ID,
         SHIP_PRIORITY_ID,
         EMAIL,
         TRADE_AREA,
         SCNALIAS,
         XDOCK_HANDLING_TIME,
         SHPPTY,
         XDOCK_LIVE_LOADING,
         OWNER,
         PORT_CODE,
         NOTES,
	count(*) over(partition by addr1 order by addr1) addr1_count
  FROM   LOCATION
)
where addr1_count > 1
; 

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0
 
QlemoConnect With a Mentor Batchelor, Developer and EE Topic AdvisorCommented:
Select
....
from Location join (
SELECT COUNT(*) CNT,
    ADDR1
FROM 
      LOCATION
GROUP BY ADDR1
HAVING COUNT > 1) cnt
on location.addr1 = cnt.addr1;

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0
 
Wilder1626Author Commented:
Many thanks, now it work great
0
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