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SQL - Date difference excluding weekends

Hello experts,

I have a need to calculate the number of business days between 2 dates and need to exclude business days.

I found this example, but it's not recognizing "TO_CHAR".

select sysdate - creation_dttm
- 2 * (to_char(sysdate, 'WW') - to_char(creation_dttm, 'WW'))
from the_table

Any ideas?
0
holemania
Asked:
holemania
2 Solutions
 
Kyle AbrahamsSenior .Net DeveloperCommented:
From http://msdn.microsoft.com/en-us/library/ms189794(v=sql.90).aspx:

CREATE FUNCTION "fnGetBusinessDays"
(
@startdate datetime,
@enddate datetime
)
RETURNS integer
AS
BEGIN
DECLARE @days integer

SELECT @days = 
DATEDIFF(d,@startdate,@enddate) 
- DATEDIFF(wk,@startdate,@enddate) * 2 
- CASE 
WHEN DATENAME(dw, @startdate) <> 'Saturday' AND DATENAME(dw, @enddate) = 'Saturday' THEN 1 
WHEN DATENAME(dw, @startdate) = 'Saturday' AND DATENAME(dw, @enddate) <> 'Saturday' THEN -1 
ELSE 0
END
- (SELECT COUNT(*) FROM holidays WHERE bankholiday BETWEEN @startdate AND @enddate AND DATENAME(dw, bankholiday) <> 'Saturday' AND DATENAME(dw, bankholiday) <> 'Sunday')

RETURN (@days)

END
GO

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0
 
sdstuberCommented:
your tags say sql2005, but your sample syntax is for Oracle

so, here's an oracle sql method

  SELECT
           (TRUNC(SYSDATE) - TRUNC(creation_dttm))
         - NVL(
               (    SELECT COUNT(
                               CASE
                                   WHEN TO_CHAR(creation_dttm + LEVEL - 1, 'Dy') IN ('Sat', 'Sun')
                                   THEN  1                                
                               END
                           )
                      FROM DUAL
                CONNECT BY LEVEL < (TRUNC(SYSDATE) - TRUNC(creation_dttm))),
               0
           ) diff            
    FROM the_table
0
 
PortletPaulfreelancerCommented:
yep, it's confusing when the topics/tags say one thing but the query says another

so if SQL Server: here's a TSQL method without needing a function
SELECT
  ID
,  (DATEDIFF(dd, creation_dttm, getdate()) + 1)
  -(DATEDIFF(wk, creation_dttm, getdate()) * 2)
  -(CASE WHEN DATENAME(dw, creation_dttm) = 'Sunday' THEN 1 ELSE 0 END)
  -(CASE WHEN DATENAME(dw, getdate()) = 'Saturday' THEN 1 ELSE 0 END)
  as working_days
, <<other fierlds >>
from your_table

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0
 
holemaniaAuthor Commented:
Sorry I saw an example and posted here.  Didn't know it was oracle, but yes I'm looking for SQL.  Thank you.
0
 
holemaniaAuthor Commented:
Thanks.
0
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