I wanted to check my logic for the following question:
"You are contemplating a take-off at a high aerodrome(1460ft elevation) on a hot day(temperature 29 degrees Celsius). Approximately what is the current density altitude if the QNH is 1013mb?
The answer is 3500?
Density altitude= pressure altitude + (120x (OAT-ISA))
So taking isa at sea level as 15 degrees Celsius and -2 for every 1000 feet then isa at say 1500 feet 12degrees Celsius.
29-12= 17 x 120->2040
2040 + 1013= 3053
Am I just being to approximate with my answer or am I doing something wrong?
Thanks for the help.