ross13
asked on
Density altitude aviation
I wanted to check my logic for the following question:
"You are contemplating a take-off at a high aerodrome(1460ft elevation) on a hot day(temperature 29 degrees Celsius). Approximately what is the current density altitude if the QNH is 1013mb?
The answer is 3500?
Density altitude= pressure altitude + (120x (OAT-ISA))
So taking isa at sea level as 15 degrees Celsius and -2 for every 1000 feet then isa at say 1500 feet 12degrees Celsius.
29-12= 17 x 120->2040
2040 + 1013= 3053
Am I just being to approximate with my answer or am I doing something wrong?
Thanks for the help.
Regards,
Ross
"You are contemplating a take-off at a high aerodrome(1460ft elevation) on a hot day(temperature 29 degrees Celsius). Approximately what is the current density altitude if the QNH is 1013mb?
The answer is 3500?
Density altitude= pressure altitude + (120x (OAT-ISA))
So taking isa at sea level as 15 degrees Celsius and -2 for every 1000 feet then isa at say 1500 feet 12degrees Celsius.
29-12= 17 x 120->2040
2040 + 1013= 3053
Am I just being to approximate with my answer or am I doing something wrong?
Thanks for the help.
Regards,
Ross
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ASKER
Thanks for that. When I was thinking pressure altitude as you said I took the pressure of 1013 and not 1460.
Thanks for the help.
Cheers,
Ross
Thanks for the help.
Cheers,
Ross
You're welcome. Happy Flying :)
Using this calculator http://wahiduddin.net/calc/calc_da_rh.htm I get 3400ft
You dont give a figure for dew point or RH, so I used 0% RH