Solved

Previous Formula Check

Posted on 2013-06-28
3
222 Views
Last Modified: 2013-07-05
I'm trying to use the previous function to check to see if I have duplicate departments in my detail.

my formula is : if dept = previous(dept) then 1 else 0

I though that by using the previous formula, I would get whats listed in the expect result.
Can you guys help me get the expected result by either using the previous command or something else.

Thanks

This is what I currently have:

Dept      DupCheck       Expected Result
01000    1                     0
01000    1                     1
01200    1                     0
01200    1                     1
0
Comment
Question by:metalteck
3 Comments
 

Author Comment

by:metalteck
ID: 39285827
I got the formula to work:
if next({dept.ACCT_UNIT}) <> previous({dept.ACCT_UNIT}) then 1 else 0

Problem I get now is that I can't use it to evaluate my running total.
I get the following error message:
Running Total cannot refer to a print time formula.

Does anyone have any suggestion as to how I can correct this?
0
 
LVL 100

Accepted Solution

by:
mlmcc earned 500 total points
ID: 39286131
What are you trying to total?

Try this

In the report header add a formula
WhilePrintingRecords;
Global numberVar DuplicateTotal;
DuplicateTotal := 0;
""

Change your formula
WhilePrintingRecords;
Global numberVar DuplicateTotal;

If Not OnFirstRecord AND {Dept} = Previous({Dept}) then
    DuplicateTotal :=DuplicateTotal + 1;
""

In the report footer to display the number of duplicates
WhilePrintingRecords;
Global numberVar DuplicateTotal;

mlmcc
0
 
LVL 34

Expert Comment

by:James0628
ID: 39286475
FWIW, your original formula looks OK (except that it should check OnFirstRecord, like in mlmcc's formula).  I don't see how that formula could give you 1 on the first 01200 line.

 OTOH, your second formula, with Next <> Previous doesn't really make sense, because it's not even looking at the current record.

 Anyway, like mlmcc said, what are you trying to total (in your running total)?

 If you just want to know if there are duplicates, or how many there are, you could use Count ({dept.ACCT_UNIT}) and DistinctCount ({dept.ACCT_UNIT}).

 If you're trying to total some fields and only want to add them once for each "duplicate" record, there are ways to handle that.  For example, if the records are sorted by {dept.ACCT_UNIT}, you could have a running total evaluate "On change of" {dept.ACCT_UNIT}, so it only adds to the total when that field changes.

 James
0

Featured Post

Better Security Awareness With Threat Intelligence

See how one of the leading financial services organizations uses Recorded Future as part of a holistic threat intelligence program to promote security awareness and proactively and efficiently identify threats.

Join & Write a Comment

I hate sub reports and always consider them the last resort in any reporting solution.  The negative effect on performance and maintainability is just not worth the easy ride they give the report writer.  Nine times out of ten reporting requirements…
Hot fix for .Net Crystal Reports 10.2.3600.0 to fix problems with sub reports running on 64 bit operating systems ISSUE: Reports which contain subreports fail with error "Missing Parameter Value" DEPLOYMENT SERVER OS: Windows 2008 with 64 bi…
Illustrator's Shape Builder tool will let you combine shapes visually and interactively. This video shows the Mac version, but the tool works the same way in Windows. To follow along with this video, you can draw your own shapes or download the file…
This video gives you a great overview about bandwidth monitoring with SNMP and WMI with our network monitoring solution PRTG Network Monitor (https://www.paessler.com/prtg). If you're looking for how to monitor bandwidth using netflow or packet s…

746 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

13 Experts available now in Live!

Get 1:1 Help Now