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Conditional Computed Columns in SQL Server Views

Posted on 2013-06-28
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Last Modified: 2013-06-29
I am trying to create a SQL Server 2008 View from an existing Table Students with the following Query it gives me an error mentioned below (Also attached)

SELECT Std_ID, Name, Sub1, Sub2, IIf ((Sub1 + Sub2)>160, 'A',IIf ((Sub1 + Sub2)>100, 'B','C')) As Legend FROM dbo.Student

Error in list of function arguments: '>' not recognized. Unable to parse query text.

I am expecting the view with the calculated field 'Legend'

Query execute perfectly in Query Designer but view is not created.

Please advice
error.jpg
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Question by:jkvaman
4 Comments
 
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Assisted Solution

by:didnthaveaname
didnthaveaname earned 125 total points
ID: 39286119
I feel like you can't use IIF in a view.  Why don't you try it in a case statement and see if that works?

SELECT 
   Std_ID, 
   Name, 
   Sub1, 
   Sub2, 
   case
      when (Sub1 + Sub2) > 160 then 'A'
      when (Sub1 + Sub2) > 100 then 'B'
      else 'C'
   end as Legend 
FROM 
   dbo.Student;

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Expert Comment

by:DOSLover
ID: 39286144
The statement looks fine. Can you please post the complete 'Create View' statement?
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Accepted Solution

by:
PortletPaul earned 125 total points
ID: 39286176
SQL Server 2012 IIF is a shorthand way for writing a CASE expression.
use the case expressions provided by didnthaveaname

try: IIF in 2008 (don't work)
try: IIF in 2012 does work

I personally would use case expressions anyway :)
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Author Closing Comment

by:jkvaman
ID: 39286461
Thanks for the quick response, unfortunately we cannot to upgrade to version 2012. So better  use Case statement suggested by  didnthaveaname. I would also accept the answer from  PortletPaul as this gives a complete solution.
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