perlperl
asked on
operator overload
I am confused how C++ calls this function internally
class MyClass {
public:
int num;
MyClass(int val) : num(val) {}
};
MyClass& decode_32(uint32_t& in, MyClass& r);
MyClass& operator >> (MyClass& s, uint32_t& v)
{
return decode_32(v, s);
}
MyClass& decode_32(uint32_t& in, MyClass& r) {
in = r.num;
return r;
}
int main(int argc, char *argv[]){
MyClass obj(10);
uint32_t val;
obj >> val; // HOW Does this call overloaded ">>" operator
printf ("Val = %d\n", val);
}
It is so difficult to read this ;) ASKER CERTIFIED SOLUTION
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Kinda specialm yes, ad well as the requirement for the overloaded operator to return a reference to the left-hand-side object they are working on. This is needed to be able to 'chain' such calls, as the language explicitly allows that.
ASKER
Thanks a lot jkr.
ASKER