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# Java Math question

I am having problems solving this math problem. I am doing this for fun. The answer is 13.0 but I don't understand I how they came up with the solution.

7 - 2 + Math.log10(1000) + Math.log(Math.pow(Math.E, 5))

I understand

7 -2 + Math.log10(1000) = 8

I not sure if about the second half of the problem.

Math.log(Math.pow(Math.E, 5)

Is the 5 that is used to raise E to the fifth power? The same 5 added to 8.

If so can someone explain this to me?

Thanks for your help.

7 - 2 + Math.log10(1000) + Math.log(Math.pow(Math.E, 5))

I understand

7 -2 + Math.log10(1000) = 8

I not sure if about the second half of the problem.

Math.log(Math.pow(Math.E, 5)

Is the 5 that is used to raise E to the fifth power? The same 5 added to 8.

If so can someone explain this to me?

Thanks for your help.

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Thanks d-glitch for the explanation. I wasn't sure.

Also thanks to Venablili!!!

Also thanks to Venablili!!!

http://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#E

and

http://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#pow(double, double)

have pretty good explanation of both log and pow (and how the result of the whole thing end up being the second parameter of the pow :)

PS: d-glitch got it - I am just throwing a couple of links to help with the understanding. :)