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I am a little uncertain with this question
f (x) = 1/(2x - 4)+ 3.

If ( p, q) is any point on the graph of y = f (x), show that the equation of the tangent to y = f (x) at this
point can be written as (2p – 4)2(y – 3) = –2x + 4p – 4.
1 Solution
First you need to find the derivative of f(x).  That will give you the slope every where.

Then you need to use the point-slope form of the equation for a line, and do the algebraic manipulation to eliminate q.

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