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Hi,<br />
<br />
I am a little uncertain with this question<br />
f (x) = 1/(2x - 4)+ 3.<br />
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If ( p, q) is any point on the graph of y = f (x), show that the equation of the tangent to y = f (x) at this<br />
point can be written as (2p – 4)2(y – 3) = –2x + 4p – 4.
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Hi,

I am a little uncertain with this question
f (x) = 1/(2x - 4)+ 3.

If ( p, q) is any point on the graph of y = f (x), show that the equation of the tangent to y = f (x) at this
point can be written as (2p – 4)2(y – 3) = –2x + 4p – 4.

tangent

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