asked on 8/31/2013

JQuery Running Total Dropdown Boxes

Hi All,

I have some code which was very helpful from padas here on this exchange. Padas, if you see this, then you already know the code ;)

What I have is multiple, dynamically created PHP dropdown boxes. You will see from the example code at the link below, how padas combined what I was doing into one, as well as, the image of what I want in red. What I need now, is to take the totals of all rows and provide a running total from that. In other words, I need to continue to show the running total for each row, plus, at the bottom of the page, show a running total of all sub-totals as the selections are made for each row.

Any input would be great, as always, I greatly appreciate it =)

JQuery Dropdown Running Total Example

JavaScript Web Languages and Standards Scripting Languages

Last Comment

btuskey

9/1/2013

ASKER CERTIFIED SOLUTION

leakim971

8/31/2013

THIS SOLUTION IS ONLY AVAILABLE TO MEMBERS.

View this solution by signing up for a free trial.

Members can start a 7-Day free trial and enjoy unlimited access to the platform.

See Pricing Options

Start Free Trial

btuskey

9/1/2013

ASKER

Hi leakim971,

I only made a minor change for it to plugin and work (see below). I really appreciate you taking the time to help me out on this =)

I haven't come across one person who hasn't been very helpful here, yet!

var total=0;
$('[name="shiftSelect_2"]').change(function(){ 
var className=$(this).attr('class');
total=0;
$('.'+className).each(function(){
var chosensm = $(this).val();
var asm = chosensm.split("_");
total=parseFloat(total)+parseFloat(asm[1],2);
});
$('#t_'+className).text(total);
$('input[name="'+className+'"]').val(total);
});
$('[name="shiftSelect_1"]').change(function(){ 
var className=$(this).attr('class');
total=0;
$('.'+className).each(function(){
var chosensm = $(this).val();
var asm = chosensm.split("_");
total=parseFloat(total)+parseFloat(asm[1],2);
});
$('#t_'+className).text(total);
$('input[name="'+className+'"]').val(total);
});
$("select[name^='shiftSelect_']").change(function()
{  
var big_total = 0;
$("select[name^='shiftSelect_']").each(function()
{ big_total += $(this).val().split("_").pop()*1; });
$("#big_total").text( big_total );
});

Open in new window

btuskey

9/1/2013

ASKER

As usual, another helpful person here on experts-exchange...thank you leakim971!