Generate Unique Number in SQL Server

Hi all!

I have a table with people data in it (names, addresses, etc), and I have a need to generate a unique 24 character identifier. It can be all numbers or contain letters from A to F (non-case sensitive).

Thanks!

Vernon
pittcchsAsked:
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QuinnDexCommented:
SELECT LOWER(LEFT(NEWID(),24))
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QuinnDexCommented:
this will do it without the - signs

select Left(NewID(),8)+Right(NewId(),12)+Left(NewId(),4)
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TheAvengerCommented:
As an addition: here is a shorter version that returns no dashes:

select left(replace(newid(), '-', ''),24)
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QuinnDexCommented:
if Numeric is preferable you can do it like this

Select cast(ABS(CHECKSUM(NEWID())) % 99999999 as varchar) +cast(ABS(CHECKSUM(NEWID())) % 99999999 as varchar)+cast(ABS(CHECKSUM(NEWID())) % 99999999 as varchar)

but it will have to be stored as string, int or bigint will not hold 24 digits
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netballiCommented:
you can use "NEWID()" to  generate unique keys of 36 character. If you use part of it via left() or right () or middle() function it cannot be guarantee that the value would be unique, although the chances of that happening are very rare.
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pittcchsAuthor Commented:
Thanks, everyone! I ended up just using:

REPLACE(NEWID(),'-','')

The 36-character ID will work for what I'm doing.

Thanks!
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Anthony PerkinsCommented:
While that will work there is an implicit conversion from uniqueidentifier to character data, I would therefore suggest you instead use something like this:
REPLACE(CAST(NEWID() as varchar(36)),'-','')
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Microsoft SQL Server 2008

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