Javascript Regular expression

I need 2 javascript regular expressions one where        GEI/any 3 alphabets/any 9 digits

second where                           first three alphabets should not be GEI/any 3 alphabets/any 9 digits
rohitjgc1Asked:
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leakim971PluritechnicianCommented:
Could you create a well formatted question? Thanks.
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Rainer JeschorCommented:
Hi,
perhaps this helps:
var pattern1 = /(GEI)\/[A-z]{3}\/\d{9}/g;
var pattern2 = /(?!GEI)...\/[a-z,A-Z]{3}\/\d{9}/g;

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see here:
http://jsfiddle.net/EE_RainerJ/fwUuA/

HTH
Rainer
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Terry WoodsIT GuruCommented:
@RainerJ's first pattern may cause problems if you use [A-z], as other characters (non-alpha) may occur between the ASCII codes for A and z. It also needs a start and end-of-string placeholder (^ and $) to ensure other characters aren't included at either end. It should be:

var pattern1 = /^(GEI)\/[a-zA-Z]{3}\/\d{9}$/g;

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The second pattern should have the , removed, and ^ and $ added, so:
var pattern2 = /^(?!GEI)...\/[a-zA-Z]{3}\/\d{9}$/g;

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ps: Please split the points with @RainerJ if you accept my answer...
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leakim971PluritechnicianCommented:
ok guys, going to buy a new set of glasses...
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Terry WoodsIT GuruCommented:
Rereading the question, I wonder if the 2nd pattern should be this:

var pattern2 = /^(?!GEI)[a-zA-Z]{3}\/[a-zA-Z]{3}\/\d{9}$/g;

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That means you're wanting 2 groups of 3 alpha characters, separated by /, as long as the first 3 aren't GEI.
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RobOwner (Aidellio)Commented:
I've requested that this question be deleted for the following reason:

Not enough information to confirm an answer.
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Terry WoodsIT GuruCommented:
In this case, I believe my answer was correct and deserves some points.

I recommend a split with @RainerJ's answer #39477889 (50%), and mine: #3947818 (25%), and #39478250 (25%).

Thanks!
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