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xslt problem

Hello-

I am trying to develop an xslt engine. However, when I put the raw xml file into the engine, the output is the original/complete xml file. I was trying to only extract certain data from the original xml file. The code is below

<xsl:stylesheet version="2.0" 
	xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
	xmlns:xs="http://www.w3.org/2001/XMLSchema"
	xmlns:fn="http://www.w3.org/2005/xpath-functions"
	xmlns:xdt="http://www.w3.org/2005/xpath-datatypes"
	xmlns:err="http://www.w3.org/2005/xqt-errors"
	exclude-result-prefixes="xs xdt err fn">


	<xsl:output method="xml" indent="yes"/>
	
	<xsl:template match="/">
		
<xsl:value-of select="invention-title"></xsl:value-of>
	
<xsl:value-of select="abstract"></xsl:value-of>


<xsl:value-of select="us-parties/us-applicants/us-applicant"></xsl:value-of>
<xsl:value-of select="us-parties/inventors/inventor"></xsl:value-of>
<xsl:value-of select="us-exemplary-claim"></xsl:value-of>


<xsl:value-of select="us-bibliographic-data-grant/application-reference"></xsl:value-of>
<xsl:value-of select="us-term-of-grant/us-term-of-extension"></xsl:value-of>
<xsl:value-of select="classifications-ipcr/classification-ipcr/section"></xsl:value-of>
<xsl:value-of select="classifications-ipcr/classification-ipcr/class"></xsl:value-of>
	
<xsl:value-of select="classifications-ipcr/classification-ipcr/subclass"></xsl:value-of>
<xsl:value-of select="classifications-ipcr/classification-ipcr/main-group"></xsl:value-of>
<xsl:value-of select="classifications-ipcr/classification-ipcr/subgroup"></xsl:value-of>
<xsl:value-of select="classification-national/main-classification"></xsl:value-of>


<xsl:value-of select="classification-national/further-classification"></xsl:value-of>


<xsl:value-of select="us-field-of-classification-search/classification-national/main-classification"></xsl:value-of>
<xsl:value-of select="drawings/figure"></xsl:value-of>


	</xsl:template>


</xsl:stylesheet>

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Do you have any solution, or is there a problem with my code? Thank you. Robert

ASKER CERTIFIED SOLUTION

Gertone (Geert Bormans)

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RobertGeoff

ASKER

Thank you for your comments. While they did not help exactly, because you did not have compete information, I was motivated to go back and re-write the code and now it works well. Instead of focusing on the values, I focused on copy and for-each. Robert

Gertone (Geert Bormans)

OK great

RobertGeoff

ASKER

Gertone-

As you're an xslt expert, you can help me out with one other thing. Let me know if I need to formerly post.

I'll incorpoate my xslt engine into a vb(2010) application. The xslt engine will be located at a specific url. this will allow me to distibute the application only.

do you have any sample code handy? i'll start to code later today, but having a good reference is useful. robert

Gertone (Geert Bormans)

Hi Robert,

There are some things you need to be aware of.

VB.net does not natvely support XSLT2
so this
<xsl:stylesheet version="2.0"
should be
<xsl:stylesheet version="1.0"
and there are a bunch of functions you then can not use
(likely you don't use them)

I am not a VB.net coder, so basicaly I have no clue how to call an XSLT from a VB.net application
but I usually look around...
maybe this would help
http://stackoverflow.com/questions/1187782/vb-net-apply-xsl-transformation-to-xml-file

RobertGeoff

ASKER

Thanks. That little bit about "1.0" and "2.0" was a big time saver. RD

Gertone (Geert Bormans)

welcome

RobertGeoff

ASKER

Gertone-

FYI, My final code is below. You may find it useful in the future. But, I am trouble accessing the XSL from an online server. I have tried putting in DROPLR, but I keep getting an error message. Right now, I stuck it on Google, but I'm not sure if this will work. Do you know of a suitable way to store an XSL file on an online server for access by an application? Thanks. Robert

Public Class XSLTform

    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        Dim document As XmlDocument
        Dim savefileDialog1 As New SaveFileDialog()
        Dim output As StringWriter
        Dim navigator As XPathNavigator

        document = New XmlDocument()
        document.LoadXml(textbox1.Text)

        'load the stylesheet
        Dim xslt As New XslCompiledTransform()
        xslt.Load("C:\Users\RobertGeoff\Pictures\Patent Pie docs and programs\PatentXSLT.xsl")

        'execute the transformation and output results to a file
        xslt.Transform(textbox1.Text, "Save.Text")

        output = New StringWriter()
        navigator = document.CreateNavigator
        xslt.Transform(navigator, Nothing, output)

        Dim stream As FileStream = _
        New FileStream(savetxt.Text, FileMode.Create)

        Dim writer As StreamWriter = New StreamWriter(stream)
        writer.Write(output.ToString)

        ' close streams
        writer.Close()
        output.Close()

        'upon pressing the transformation button, a dialog to save the file should come up- Cf the savefiledialog sub down below.
        savefileDialog1.ShowDialog()
        savefileDialog1.Title = "Select or Enter Filename"
        savefileDialog1.Filter = "xml Files(*.xml)|*.xml|All Files|*,*"
        savefileDialog1.FilterIndex = 1
        savefileDialog1.RestoreDirectory = True

    End Sub

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Gertone (Geert Bormans)

it all depends on the .net mechanism of resolving the url in the load
it might be that you need to deactivate some security settings
I am afraid this really is a VB.net issue and I recommend that you post a question in the VB.net TA