Bash Script and Math

I want this to come out to .01 but it keeps coming out to 0
What am I doing wrong?

whatislefta=$((200/20000))

whatislefta is 0 when I run this it should be .01

Thanks for any help!!
LVL 14
RickEpnetAsked:
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MazdajaiCommented:
Bash only does integer arithmetic, for floating point use bc -

whatislefta=`echo "200/20000"|bc -l`

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TintinCommented:
You can only do integer maths in bash.

whatislefta=$(echo 'scale=2;200/2000'|bc)
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MazdajaiCommented:
To control floating points, you can use the printf, that is derived from C -

printf "%.3f\n" $whatislefta

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Rajesh NandanwarCommented:
Float value in a variablewhatislefta=$(echo '200/20000' | bc -l)
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ozoCommented:
What would you wish to do with a .01 result?
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Gerwin Jansen, EE MVETopic Advisor Commented:
You could strip the trailing zeros like this:
a=$(echo '200/20000' | bc -l | sed "s/[0]*$//") ; echo $a

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RickEpnetAuthor Commented:
OK this seems to work but down the script I have some if statements and it throws an error it says  " line 95: [: .01: integer expression expected"

Here is the if statement.  $warn is an integer.

   if [ $whatislefta -gt $warn ]
   then
      ex=0
      condition="OK"
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ozoCommented:
instead of
if [ $((200/20000)) -gt $warn ]
you can do
if [ 200 -gt $(($warn*20000)) ]
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RickEpnetAuthor Commented:
I have work out over the next 2 days so I may not be able to look at this until Friday.

Thanks I will let you know as soon as I have time to look at this again.
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skullnobrainsCommented:
if you have a decent expr version around, it will handle floating point arithmetic using the '-e' switch

you'd probably work it out much easier by multiplying your initial number and the treshold by 1000 or more and work with integers
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